二分查找:在一组数中找到指定的数

//1. 存储在数组中(如果是链表则无法使用二分查找)
//2. 有序的排列 (递增或递减,或重复数都无影响)

递归法:

//param:有序数组,检索开始为止,结束为止,要查找的数字
//return:返回目标数字所在为止,没有找到返回-1
int binSearch (int arr[], int low, int high, int key) {
    if (low <= high) {
        int mid = (low + high)/2;
        if (key == arr[mid]) return mid;
        else if (key < arr[mid]) return binSearch(arr,low,mid-1,key);
        else if (key > arr[mid]) return binSearch(arr,mid+1,high,key);
    } else return -1;
}

循环查找:

//param:有序数组,数组大小,需要查找的数
//return:查找的数所在位置,找不到返回-1
int binSearch (int *arr, int size, int key) {
    if (arr == NULL || size == 0) return -1;
    int low = 0, high = size -1, mid = 0;
    while (low<=high) {
        mid = (low+high)/2;
        if (arr[mid] < key) low = mid + 1;
        else if (arr[mid] > key) high = mid - 1;
        else return mid;
    }
    return -1;
}

参考原文:https://blog.csdn.net/idream68/article/details/89352653

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