1.

select xuehao,name1,dengji=
case
when zongfenshu <50 then '不及格'
when zongfenshu >=50 and zongfenshu <=60 then '合格'
else '优秀'
end from aaa where zhuanyeming='计算机'
2.
update aaa
set zongfenshu =
case
when dengji ='及格' then zongfenshu+5
when dengji='优秀' then zongfenshu+20
else zongfenshu*2
end 

 

相关文章:

  • 2022-02-24
  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-01-25
  • 2022-12-23
猜你喜欢
  • 2021-10-03
相关资源
相似解决方案