1:delete from tab2 where id in (select id from deleted) insert into tab2 select * from inserted
2:
create table labtt
(
id int identity(1,1),
names varchar(80)
)
go
create table laburl
(
id int identity(1,1),
url varchar(200)
)

insert into labtt(names) values('/upload/img/2001/1122.jpg')

create trigger aa on labtt
(

)
select * from labtt

delete from labtt where id=2

delete from labtt where id in(6,7,5)

select * from laburl


alter trigger trsss on labtt
for delete
as
begin
insert into laburl(url) select names from deleted
end

相关文章:

  • 2022-12-23
  • 2022-12-23
  • 2022-12-23
  • 2022-02-20
  • 2021-05-28
  • 2021-05-17
  • 2021-07-17
  • 2022-12-23
猜你喜欢
  • 2021-12-06
  • 2021-11-23
  • 2022-12-23
  • 2021-06-28
  • 2022-03-09
  • 2021-09-17
相关资源
相似解决方案