Reverse bits of a given 32 bits unsigned integer.

For example, given input 43261596 (represented in binary as 00000010100101000001111010011100), return 964176192 (represented in binary as 00111001011110000010100101000000).

Follow up:
If this function is called many times, how would you optimize it?

Related problem: Reverse Integer

Credits:
Special thanks to @ts for adding this problem and creating all test cases.

Analysis:

Shift result to left by 1 bit, get the last bit of n, put the bit onto result.

Solution:

public class Solution {
    // you need treat n as an unsigned value
    public int reverseBits(int n) {
        if (n==0) return 0;
        
        int res = 0;
        for (int i=0;i<32;i++){
            res = (res << 1);
            if ((n & 1)==1) res++;
            n = n >> 1;
        }
        return res;
    }
}

 

相关文章:

  • 2022-01-01
  • 2021-06-24
  • 2021-12-11
  • 2021-12-04
  • 2022-01-07
  • 2021-07-22
  • 2022-12-23
  • 2022-12-23
猜你喜欢
  • 2021-07-30
  • 2022-03-01
  • 2021-11-17
  • 2022-12-23
  • 2021-06-22
相关资源
相似解决方案