SELECT table_name, LEFT(column_names , LEN(column_names )-1) AS column_names
FROM information_schema.columns AS extern
CROSS APPLY
(
SELECT column_name + ','
FROM information_schema.columns AS intern
WHERE extern.table_name = intern.table_name
FOR XML PATH('')
) pre_trimmed (column_names)

--where table_name ='表名'
GROUP BY table_name, column_names;

相关文章:

  • 2021-07-19
  • 2021-05-29
  • 2021-11-03
  • 2021-05-21
  • 2022-02-14
  • 2021-07-01
  • 2022-12-23
  • 2021-07-02
猜你喜欢
  • 2021-09-02
  • 2022-01-27
  • 2022-01-18
  • 2022-12-23
  • 2022-02-15
  • 2021-12-08
相关资源
相似解决方案