Xslt中递归的实现

<?xml version="1.0" encoding="gb2312"?>
<xsl:stylesheet version="1.0" xmlns:xsl="http://www.w3.org/1999/XSL/Transform" xmlns:fo="http://www.w3.org/1999/XSL/Format">
    <xsl:template match="/">
        <!--      addFunction(addString,currentNum,theResult)     -->
        <xsl:call-template name="addFunction">
            <xsl:with-param name="addString" >1</xsl:with-param>
            <xsl:with-param name="currentNum">1</xsl:with-param>
            <xsl:with-param name="theResult" >1</xsl:with-param>
     </xsl:call-template>
     
    </xsl:template>

    <!-- 
        void addFunction(string addString,int currenNum,int thgeResult) 
        {
            Console.Write(addString + "+" + currenNum.ToString() + " =");
            Console.WriteLine((currenNum+thgeResult).ToString());

            if (currentNum<10)
            {
                addFunction(addString+"+"+currentNum.ToString(),currenNum+1,thgeResult+currenNum); 
            }
        }
    -->
    <xsl:template name="addFunction">
        <xsl:param name="addString"/>
        <xsl:param name="currentNum"/>
        <xsl:param name="theResult"/>
        
        <xsl:value-of select="concat($addString,'+',$currentNum)"/> = 
        <xsl:value-of select="$theResult + $currentNum"/>
        <br/>
        <xsl:if test="$currentNum &lt;= 10 ">
            <xsl:call-template name="addFunction">
                <xsl:with-param name="addString" select="concat($addString,'+',$currentNum)"/>
                <xsl:with-param name="currentNum" select="$currentNum + 1"/>
                <xsl:with-param name="theResult" select="$theResult + $currentNum"/>
            </xsl:call-template>
         </xsl:if>
    </xsl:template>
</xsl:stylesheet>