import re pattern = re.compile(u'[\uD800-\uDBFF][\uDC00-\uDFFF]') pattern.sub('',text) 相关文章： 2021-09-11 2022-12-23 2022-12-23 2021-09-24 2021-06-02 2022-12-23 2022-03-02 2021-12-27