select
        (@i:[email protected]+1) numbers,                p.id,         p.post_name as name,         p.parent_id as pid,         p.level,         p.value,         p.remark,         p.create_time as createTime         from reversion_post_info p left join reversion_post_info i on p.parent_id = i.id,(SELECT @i:=0) as numbers order by p.create_time desc

 

结果如下:

Mysql查询得到的数据自动为结果排上序号

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