使用python从纯文本中提取包含空值的字符串

Question

我有一个字符串

a='S
LINC             SHORT LEGAL                                   TITLE NUMBER
0037 471 661     1720278;16;21                                 172 211 342

LEGAL DESCRIPTION
PLAN 1720278  
BLOCK 16  
LOT 21  
EXCEPTING THEREOUT ALL MINES AND MINERALS  

ESTATE: FEE SIMPLE  
ATS REFERENCE: 4;24;54;2;SW

MUNICIPALITY: CITY OF EDMONTON

REFERENCE NUMBER: 172 023 641 +71

---------------------------------------------------------------------------- 
----
                     REGISTERED OWNER(S)
REGISTRATION    DATE(DMY)  DOCUMENT TYPE      VALUE           CONSIDERATION
----------------------------------------------------------------------------- 
---

172 211 342    15/08/2017                      $610,000        CASH & MTGE'

需要提取文档类型、值和考虑值以下的值并输出到类似['','$610,000','CASH & MTGE'] 的数组中 我尝试使用findall(r'(?<!\S)(?:[$]\S+|[^$\d]+)\b', a)。但我只能得到 ['$610,000','CASH & MTGE'] 并且没有文档类型的值，因为它是空的。

Answer 1

据我了解，您想从字符串中返回一个值为$610,000 CASH & MTGE' 的数组吗？

假设最终保留所需的字符串值，我们可以利用splitlines 函数。然后，使用len(a)-1 获取所需的字符串，如下所示：

>>> a='''S
LINC             SHORT LEGAL                                   TITLE NUMBER
0037 471 661     1720278;16;21                                 172 211 342

LEGAL DESCRIPTION
PLAN 1720278  
BLOCK 16  
LOT 21  
EXCEPTING THEREOUT ALL MINES AND MINERALS  

ESTATE: FEE SIMPLE  
ATS REFERENCE: 4;24;54;2;SW

MUNICIPALITY: CITY OF EDMONTON

REFERENCE NUMBER: 172 023 641 +71

---------------------------------------------------------------------------- 
----
                     REGISTERED OWNER(S)
REGISTRATION    DATE(DMY)  DOCUMENT TYPE      VALUE           CONSIDERATION
----------------------------------------------------------------------------- 
---

172 211 342    15/08/2017                      $610,000        CASH & MTGE'''

>>> b=a.splitlines()
>>> req_line = b[len(b)-1]
>>> print(req_line)