如何实现最多 N 个级别的递归在 Node js 中的每个级别都有对象数组？答案

【问题标题】：How to Implement recursion upto N levels Having array of objects at each level in Node js?如何实现最多 N 个级别的递归在 Node js 中的每个级别都有对象数组？
【发布时间】：2019-03-19 13:42:05
【问题描述】：

我想为此链接中给出的 json 实现递归 Check JSON Here 我的递归解决方案只适用于一个级别，所以请向我推荐这样的解决方案，以便我可以工作到 N 级。

我已经写了一个递归函数，但它只能工作到一个级别。

Report.GetSections = function(Section1) {
  let TempSectionItem = [];
  let TempAllSection = [];

  let sortOrder = 0;
  let id = Section1.id;
  let parentId = Section1.parentId;
  let title = Section1.label;
  sortOrder = Section1.SortOrder;
  let SectionType = Section1.sectionType;

  if (Section1.sections.length === 0) {
    let TempSectionItem = [];
    let allsection = [];
    let tempsection1 = [];
    let tempsection = new Section(id, title, parentId, SectionType, sortOrder, TempSectionItem, allsection);
    tempsection1.push(tempsection);
    return tempsection1;
  }
  for (let i = 0; i < Section1.sections.length; i++) {

    var tempsection = new Section(id, title, parentId, SectionType, sortOrder, TempSectionItem, Report.GetSections(Section1.sections[i]));
    TempAllSection.push(tempsection);

  }

  return TempAllSection;
}

【问题讨论】：

标签： javascript node.js recursion

【解决方案1】：

这是上述问题的递归解决方案。

  class Section {
  constructor(id, title, parentId, sectionType, sortOrder, sectionItem, section) {
    this.id = id;
    this.title = title;
    this.parentId = parentId;
    this.sectionType = sectionType;
    this.section = section;
    this.sortOrder = sortOrder;
    this.SectionItems = sectionItem;

  }
}

这里是递归函数：

  Report.GetSections = function (Section1) {
    let TempSectionItem = [];let sortOrder = 0;
    let id = Section1.id;
    let parentId = Section1.parentId;
    let title = Section1.label;
    sortOrder = Section1.sortOrder;
    let SectionType = Section1.sectionType;
if (Section1.sections.length === 0) {
      let allsection = [];
      let tempsection = new Section(id, title, parentId, SectionType, sortOrder, TempSectionItem, allsection);
      return tempsection;
    }

    let TempLevelSections=[];
    for (let i = 0; i < Section1.sections.length; i++) {
      TempLevelSections.push(Report.GetSections(Section1.sections[i]));
    }
    var section=new Section(id, title, parentId, SectionType, sortOrder, TempSectionItem, TempLevelSections);
    return section;
  }

【讨论】：