【发布时间】:2018-10-23 06:07:48
【问题描述】:
背景:为了让开发人员能够在易于使用的环境中构建和单元测试代码,我们构建了一个本地 Spark 环境,并集成了其他工具。但是,我们还想从本地环境访问 S3 和 Kinesis。当我们使用假设角色(根据我们的安全标准)从本地 Pyspark 应用程序访问 S3 时,它会引发禁止错误。
仅供参考 - 我们采用以下访问模式来访问 AWS 账户上的资源。 assume-role access pattern
测试代码access-s3-from-pyspark.py:
from pyspark import SparkConf, SparkContext
conf = SparkConf().setAppName("s3a_test").setMaster("local[1]")
sc = SparkContext(conf=conf)
sc.setSystemProperty("com.amazonaws.services.s3.enableV4", "true")
hadoopConf = {}
iterator = sc._jsc.hadoopConfiguration().iterator()
while iterator.hasNext():
prop = iterator.next()
hadoopConf[prop.getKey()] = prop.getValue()
for item in sorted(hadoopConf.items()):
if "fs.s3" in item[0] :
print(item)
path="s3a://<your bucket>/test-file.txt"
## read the file for testing
lines = sc.textFile(path)
if lines.isEmpty() == False:
lines.saveAsTextFile("test-file2.text")
属性文件spark-s3.properties
spark.hadoop.fs.s3a.impl org.apache.hadoop.fs.s3a.S3AFileSystem
spark.hadoop.fs.s3a.endpoint s3.eu-central-1.amazonaws.com
spark.hadoop.fs.s3a.access.key <your access key >
spark.hadoop.fs.s3a.secret.key <your secret key>
spark.hadoop.fs.s3a.assumed.role.sts.endpoint sts.eu-central-1.amazonaws.com
spark.hadoop.fs.s3a.aws.credentials.provider org.apache.hadoop.fs.s3a.TemporaryAWSCredentialsProvider
spark.hadoop.fs.s3a.aws.credentials.provider org.apache.hadoop.fs.s3a.AssumedRoleCredentialProvider
spark.hadoop.fs.s3a.aws.credentials.provider org.apache.hadoop.fs.s3a.auth.AssumedRoleCredentialProvider
spark.hadoop.fs.s3a.assumed.role.session.name testSession1
spark.haeoop.fs.s3a.assumed.role.session.duration 3600
spark.hadoop.fs.s3a.assumed.role.arn <role arn>
spark.hadoop.fs.s3.canned.acl BucketOwnerFullControl
如何运行代码:
spark-submit --properties-file spark-s3.properties \
--jars jars/hadoop-aws-2.7.3.jar,jars/aws-java-sdk-1.7.4.jar \
access-s3-from-pyspark.pyenter code here
以上代码返回以下错误,请注意我可以通过 CLI 和 boto3 使用假设角色配置文件或 api 访问 S3。
com.amazonaws.services.s3.model.AmazonS3Exception: Status Code: 403, AWS Service: Amazon S3, AWS Request ID: 66FB4D6351898F33, AWS Error Code: null, AWS Error Message: Forbidden, S3 Extended Request ID: J8lZ4qTZ25+a8/R3ZeBTrW5TDHzo98A9iUshbe0/7VcHmiaSXZ5u6fa0TvA3E7ZYvhqXj40tf74=
at com.amazonaws.http.AmazonHttpClient.handleErrorResponse(AmazonHttpClient.java:798)
at com.amazonaws.http.AmazonHttpClient.executeHelper(AmazonHttpClient.java:421)
at com.amazonaws.http.AmazonHttpClient.execute(AmazonHttpClient.java:232)
at com.amazonaws.services.s3.AmazonS3Client.invoke(AmazonS3Client.java:3528)
at com.amazonaws.services.s3.AmazonS3Client.getObjectMetadata(AmazonS3Client.java:976)
at com.amazonaws.services.s3.AmazonS3Client.getObjectMetadata(AmazonS3Client.java:956)
at org.apache.hadoop.fs.s3a.S3AFileSystem.getFileStatus(S3AFileSystem.java:892)
at org.apache.hadoop.fs.s3a.S3AFileSystem.getFileStatus(S3AFileSystem.java:77)
at org.apache.hadoop.fs.Globber.getFileStatus(Globber.java:57)
at org.apache.hadoop.fs.Globber.glob(Globber.java:252)
at org.apache.hadoop.fs.FileSystem.globStatus(FileSystem.java:1676)
at org.apache.hadoop.mapred.FileInputFormat.singleThreadedListStatus(FileInputFormat.java:259)
at org.apache.hadoop.mapred.FileInputFormat.listStatus(FileInputFormat.java:229)
at org.apache.hadoop.mapred.FileInputFormat.getSplits(FileInputFormat.java:315)
at org.apache.spark.rdd.HadoopRDD.getPartitions(HadoopRDD.scala:200)
at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:253)
at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:251)
at scala.Option.getOrElse(Option.scala:121)
at org.apache.spark.rdd.RDD.partitions(RDD.scala:251)
at org.apache.spark.rdd.MapPartitionsRDD.getPartitions(MapPartitionsRDD.scala:35)
at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:253)
at org.apache.spark.rdd.RDD$$anonfun$partitions$2.apply(RDD.scala:251)
at scala.Option.getOrElse(Option.scala:121)
at org.apache.spark.rdd.RDD.partitions(RDD.scala:251)
at org.apache.spark.api.java.JavaRDDLike$class.partitions(JavaRDDLike.scala:61)
at org.apache.spark.api.java.AbstractJavaRDDLike.partitions(JavaRDDLike.scala:45)
at sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
at sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:62)
at sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:43)
at java.lang.reflect.Method.invoke(Method.java:498)
at py4j.reflection.MethodInvoker.invoke(MethodInvoker.java:244)
at py4j.reflection.ReflectionEngine.invoke(ReflectionEngine.java:357)
at py4j.Gateway.invoke(Gateway.java:282)
at py4j.commands.AbstractCommand.invokeMethod(AbstractCommand.java:132)
at py4j.commands.CallCommand.execute(CallCommand.java:79)
at py4j.GatewayConnection.run(GatewayConnection.java:238)
at java.lang.Thread.run(Thread.java:748)
问题:
这是正确的做法吗?
有没有其他简单的方法可以在本地使用 AWS 资源进行开发和测试(我还探索了 localstack 包,它在大多数情况下都可以工作,但仍然不完全可靠)
我是否为此使用了正确的罐子?
【问题讨论】:
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标签: apache-spark amazon-s3 pyspark