【发布时间】:2020-09-22 10:49:38
【问题描述】:
你好,我有两个表:user_info,ip_location,一个是50,000,另一个是100,000。 现在需要使用user表的ip来查看归属地,将ip转换为int并与ip_location比较interval。
我的hive版本是3.0.0,这个版本没有索引。
ip_location: enter image description here
这个操作在pg中非常快:
set search_path=res;
select * from(
select ip,
(split_part(ip,'.',1)::bigint*256*256*256
+split_part(ip,'.',2)::bigint*256*256
+split_part(ip,'.',3)::bigint*256
+split_part(ip,'.',4)::bigint)::int8 as ipvalue
from user_info) t1
left join ip_location t2 on
ipv4_val_begin=(select max(ipv4_val_begin) from ip_location where ipv4_val_begin <= ipvalue);
但我没有在 hive 上找到此语法的替代方法:
select ip,
t2.location_country
cast(split(ip,"\\.")[0] as bigint)*256*256*256
+cast(split(ip,"\\.")[0] as bigint)*256*256
+cast(split(ip,"\\.")[0] as bigint)*256
+cast(split(ip,"\\.")[0] as bigint) as ipvalue
from source.v_dm_vip_user t1
left join res.ip_location t2 on
ipv4_val_begin=(select max(ipv4_val_begin) from res.ip_location where ipv4_val_begin <= ipvalue);
错误: enter image description here
改成如下sql,可以查询成功,但是很慢,需要1天:
select ip,
t2.location_country
cast(split(ip,"\\.")[0] as bigint)*256*256*256
+cast(split(ip,"\\.")[0] as bigint)*256*256
+cast(split(ip,"\\.")[0] as bigint)*256
+cast(split(ip,"\\.")[0] as bigint) as ipvalue
from source.v_dm_vip_user t1
left join res.ip_location t2 on
cast(split(ip,"\\.")[0] as bigint)*256*256*256
+cast(split(ip,"\\.")[0] as bigint)*256*256
+cast(split(ip,"\\.")[0] as bigint)*256
+cast(split(ip,"\\.")[0] as bigint) > ipv4_val_begin
and
cast(split(ip,"\\.")[0] as bigint)*256*256*256
+cast(split(ip,"\\.")[0] as bigint)*256*256
+cast(split(ip,"\\.")[0] as bigint)*256
+cast(split(ip,"\\.")[0] as bigint) < ipv4_val_end;
有没有更好更快的sql?试了很多次还是不行,谢谢。
【问题讨论】:
-
你有支持
with子句的hive版本吗? -
with子句提速不了,还是需要一天左右,postgres只用了20秒