【问题标题】:Play! async action akka AskTimeoutException玩!异步动作 akka AskTimeoutException
【发布时间】:2012-12-29 04:18:52
【问题描述】:

我正在尝试使用 akka Actor 使用 ask 模式发出最简单的异步请求,但无论如何我都会收到 akka.pattern.AskTimeoutException。我有的是这样的:

object Users extends Controller {

  def newUser = {
    val actor = Akka.system.actorOf(Props[UserRegistration])
    ActorAction[String](actor, "hello")(Ok(_))
  }
}

ActorAction 是通常的Async 的包装器:

object ActorAction {

  def apply[A](actorRef: ActorRef, msg: AnyRef, timeout: Timeout = 5 seconds)(f: A => Result)(implicit m: Manifest[A]): Action[AnyContent] = {
    Action {
      AsyncResult {
        ask(actorRef, msg, timeout).mapTo[A].asPromise.map(f)
      }
    }
  }

}

演员什么都不做,只是记录接收消息并返回它:

class UserRegistration extends Actor {
  val log = Logging(context.system, this)
  def receive = {
    case u => log.info("received " + u); u
  }
}

消息的记录工作得很好。我已经尝试了一切,但没有任何效果。任何帮助都非常受欢迎!

播放:2.9.1 阿卡:2.0.2

堆栈跟踪:

[info] play - database [default] connected at jdbc:postgresql://localhost:5432/ss_dev
[info] play - Application started (Dev)
[info] play - Starting application default Akka system.
[INFO] [12/28/2012 22:10:42.51] [application-akka.actor.default-dispatcher-1] [akka://application/user/$a] received hello
[error] play - Waiting for a promise, but got an error: Timed out
akka.pattern.AskTimeoutException: Timed out
at akka.dispatch.DefaultPromise.result(Future.scala:875) [akka-actor.jar:2.0.2]
at akka.dispatch.Await$.result(Future.scala:74) ~[akka-actor.jar:2.0.2]
at play.api.libs.concurrent.AkkaPromise.await(Akka.scala:43) ~[play_2.9.1.jar:2.0.4]
at play.api.libs.concurrent.Promise$class.await(Promise.scala:55) ~[play_2.9.1.jar:2.0.4]
at play.api.libs.concurrent.AkkaPromise.await(Akka.scala:28) ~[play_2.9.1.jar:2.0.4]
at play.api.libs.concurrent.Promise$class.value(Promise.scala:53) ~[play_2.9.1.jar:2.0.4]
Caused by: akka.pattern.AskTimeoutException: Timed out
at akka.pattern.PromiseActorRef$$anonfun$1.apply$mcV$sp(AskSupport.scala:274) ~[akka-actor.jar:2.0.2]
at akka.actor.DefaultScheduler$$anon$6$$anon$7.run(Scheduler.scala:183) ~[akka-actor.jar:2.0.2]
at akka.dispatch.TaskInvocation.run(AbstractDispatcher.scala:94) [akka-actor.jar:2.0.2]
at akka.jsr166y.ForkJoinTask$AdaptedRunnableAction.exec(ForkJoinTask.java:1381) [akka-actor.jar:2.0.2]
at akka.jsr166y.ForkJoinTask.doExec(ForkJoinTask.java:259) [akka-actor.jar:2.0.2]
at akka.jsr166y.ForkJoinPool$WorkQueue.runTask(ForkJoinPool.java:975) [akka-actor.jar:2.0.2]

提前致谢!

【问题讨论】:

    标签: scala playframework-2.0 akka


    【解决方案1】:

    您没有回复消息sender ! u,请阅读 Akka 参考文档:http://doc.akka.io

    【讨论】:

    • 谢谢维克多!它确实奏效了!我认为接收方法的返回值是“回复”。非常感谢。
    • 嗨,Gerry,receive 方法没有返回任何东西(单位),这是因为你可以有 0..N 个“返回值”
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