在 Python 中提取所有父/子 Json 值答案

【问题标题】：Extract All Parent/Child Json values in Python在 Python 中提取所有父/子 Json 值
【发布时间】：2020-03-25 05:54:01
【问题描述】：

以下是输入的 Json 模式和预期的输出响应 \n

输入模式： { “要求”： { "requestId": "ABCDE", “模型类型”：“新”， "lineOfBusiness": "WC", “请求日期”：“2019-12-10”， “评估日期”：“2019-12-11”， "jobNumber": "GDERS", "branchNumber": "IODGH", "quoteEffectiveDate": "2019-12-11", "policyNumber": "12XYZ34", "policyEffectiveDate": "2019-12-10", "policyExpirationDate": "2020-12-09" }, “高级历史”：[{ "jobNumber": "GDERS", "branchNumber": "IODGH", “保单号码”： ””， "policyEffectiveDate": "2019-04-01", "policyExpirationDate": "2020-03-31", “班级代码”： [ { "classCode":"AB", "transactionDate": "2019-04-01", “交易类型”：“1”， "locationNumber": "12345", “溢价”：1200， “工资单或曝光”：100 },

                {
                "classCode":"CD",               
                "transactionDate": "2019-04-01",
                "transactionType": "1",
                "locationNumber": "12345",
                "premium": 1200,
                "payrollOrExposure": 100
                }
            ]

        },
        ]
}

Output Expected:
request.requestId = "ABCDE"
request.modelType = "NEW"
..
..
..
..
premiumHistory.jobNumber="GDERS"
premiumHistory.branchNumber="IODGH"
premiumHistory.policyNumber=""
..
premiumHistory.classCode.classCode="AB"
premimumHistory.classCode.transactionDate="2019-04-01"
..
..
..

代码需要在 python 中，我已经使用不同的技术进行了测试，但无法获得所需的输出。非常感谢任何帮助。

问候，

【问题讨论】：

如果你也发布你已经尝试过的细节，你将有更好的机会获得帮助。
请尝试修正您的格式，以便更容易看到发生了什么

标签： python json

【解决方案1】：

这是我迄今为止尝试过的

enter code here

def extract(obj, arr,parent_key):
    #Recursively search for values of key in JSON tree.
    if isinstance(obj, dict):
        for k, v in obj.items():
            print("\n Dict::",k,"::",v)
            if isinstance(v, (dict, list)):
                print("1::",k)
                parent_key=k
                extract(v, arr,parent_key)
            else:
                print("Before Append::",parent_key)
                arr.append(parent_key+"."+k+"|"+str(v))
    elif isinstance(obj, list):
        for item in obj:
            print("\n List::",item)
            extract(item, arr,parent_key)
    return arr
arr = []
parent_key=''
extract(data,arr,parent_key)

【讨论】：

【解决方案2】：

对于格式问题，我深表歉意。甚至没有意识到这一点。

以下是输入的 Json 模式和预期的输出响应 \n

输入模式：

{
    "request": {
        "requestId": "ABCDE",
        "modelType": "NEW",
        "lineOfBusiness": "WC",
        "requestDate": "2019-12-10",
        "evaluationDate": "2019-12-11",
        "jobNumber": "GDERS",
        "branchNumber": "IODGH",
        "quoteEffectiveDate": "2019-12-11",
        "policyNumber": "12XYZ34",
        "policyEffectiveDate": "2019-12-10",
        "policyExpirationDate": "2020-12-09"
    },
    "premiumHistory": [{
        "jobNumber": "GDERS",
        "branchNumber": "IODGH",
        "policyNumber": "",
        "policyEffectiveDate": "2019-04-01",
        "policyExpirationDate": "2020-03-31",
        "classCode":
            [
                {
                "classCode":"AB",
                "transactionDate": "2019-04-01",
                "transactionType": "1",
                "locationNumber": "12345",
                "premium": 1200,
                "payrollOrExposure": 100
                },

                {
                "classCode":"CD",               
                "transactionDate": "2019-04-01",
                "transactionType": "1",
                "locationNumber": "12345",
                "premium": 1200,
                "payrollOrExposure": 100
                }
            ]

        },
        ]
}

Output Expected:
request.requestId = "ABCDE"
request.modelType = "NEW"
..
..
..
..
premiumHistory.jobNumber="GDERS"
premiumHistory.branchNumber="IODGH"
premiumHistory.policyNumber=""
..
premiumHistory.classCode.classCode="AB"
premimumHistory.classCode.transactionDate="2019-04-01"
..
..
..

【讨论】：