【发布时间】:2016-05-10 11:06:08
【问题描述】:
我在以下环境中使用机器人框架。
- Python 2.7.6
- 机器人框架 2.8.7
- Ubuntu 14.04.3 LTS
如果匹配 "[0-9]*" 模式,我想从字符串中删除 " 字符。
我的代码如下,但这不能工作未知参数。
*** Settings ***
Library Collections
Library json
Library String
*** Variables ***
${TARGET_STRING} {"host": "['192.168.1.2', '192.168.1.3']", "part": "['ZZZ1', 'ZZZ2']", "name": "XXXX", "kara": null, "type": "123", "id": "YYYY", "flg": false,"type2": "4567","type3": "4"}
*** Test Cases ***
My Test Case
${resp} My Keyword ${TARGET_STRING}
*** Keywords ***
My Keyword
[Arguments] ${string}
${resp} Replace String Using Regexp ${string} "[0-9][0-9][0-9]" 123
${resp} Replace String Using Regexp ${resp} "[0-9][0-9][0-9][0-9]" 4567
${resp} Replace String Using Regexp ${resp} "[0-9]" 4
Log To Console ${resp}
输出
{"host": "['192.168.1.2', '192.168.1.3']", "part": "['ZZZ1', 'ZZZ2']", "name": "XXXX", "kara": null, "type": 123, "id": "YYYY", "flg": false,"type2": 4567,"type3": 4}
(在这种情况下,我想改变
“类型”:“123”到“类型”:123,
“type2”:“4567”到“type2”:4567,
"type3": "4" 改成 "type3": 4 不改其他)
如何概括它?
【问题讨论】:
标签: regex robotframework