Hibernate 工具不使用 Oracle 序列生成 POJO？答案

【问题标题】：Hibernate tools are not generating POJOs with Oracle sequence?Hibernate 工具不使用 Oracle 序列生成 POJO？
【发布时间】：2016-01-19 13:39:18
【问题描述】：

我正在尝试使用 Hibernate Tools eclipse 插件/Maven Hibernate 插件生成 Hibernate 实体 pojo。 POJO 生成良好，但我需要 @Id 使用 Oracle 序列，如下所示：

@Id
@GeneratedValue(strategy=GenerationType.SEQUENCE, generator="patient_sequence")
@SequenceGenerator(name="patient_sequence", sequenceName="PATIENT_SEQ")
@Column(name = "PT_KEY", unique = true, nullable = false, precision = 22, scale = 0)
public Long getPtKey() {
    return this.ptKey;
}

我尝试了以下 POST 中给出的选项： @SequenceGenerator - allocationSize, reverse engineering with Eclipse Hibernate Tools

但它没有考虑oracle序列。它正在生成@id 元素，如下所示：

@Id
@Column(name = "PT_KEY", unique = true, nullable = false, precision = 22, scale = 0)
public BigDecimal getPtKey() {
    return this.ptKey;
}

请找到 hibernate-reverse.xml 如下：

 <?xml version="1.0" encoding="UTF-8"?>
 <!DOCTYPE hibernate-reverse-engineering PUBLIC "-//Hibernate/Hibernate Reverse Engineering DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-reverse-engineering-3.0.dtd" >

<hibernate-reverse-engineering>

<schema-selection match-schema="DOC" />

<type-mapping>
    <sql-type jdbc-type="NUMERIC" hibernate-type="java.lang.Long" />
</type-mapping>

<table-filter match-name=".*"></table-filter>
<table name="Patient">
    <primary-key>
        <generator class="org.hibernate.id.SequenceGenerator">
            <param name="sequence">PATIENT_SEQ</param>
        </generator>
        <key-column name="PT_KEY" />
    </primary-key>
   </table>

</hibernate-reverse-engineering>

我在这里有什么遗漏吗？请指教。

【问题讨论】：

标签： eclipse oracle hibernate maven hibernate-tools

【解决方案1】：

小幅调整适用于这两种情况。

将 jdbc 类型从 NUMERIC 更改为 DECIMAL

<?xml version="1.0" encoding="UTF-8"?>
<!DOCTYPE hibernate-reverse-engineering PUBLIC "-//Hibernate/Hibernate Reverse Engineering DTD 3.0//EN" "http://hibernate.sourceforge.net/hibernate-reverse-engineering-3.0.dtd" >
<hibernate-reverse-engineering>
<schema-selection match-schema="DOC" />
<type-mapping>
<sql-type jdbc-type="DECIMAL" hibernate-type="java.lang.Long" />
</type-mapping>
<table-filter match-name=".*"></table-filter>
<table name="Patient">
<primary-key>
    <generator class="sequence">
        <param name="sequence">PATIENT_SEQ</param>
    </generator>
    <key-column name="PT_KEY" />
</primary-key>
</table>

【讨论】：