SQLITE 多行值到列中

Question

我有事件状态表，表结构已经定义好了，我想把几行值合并成一行。

当前表格数据：

事件：

EVENT       EVENTNAME       EVENTACTION     STATUS      TIMESTAMP
"Event1"    "FootBall"      "FootBall0"     "started"   "1554980085"
"Event1"    "TableTennis"   "TT0"           "started"   "1554980086"
"Event1"    "FootBall"      "FootBall0"     "success"   "1554980087"
"Event1"    "Chess"         "CHESS0"        "success"   "1554980095"
"Event1"    "TableTennis"   "TT0"           "running"   "1554980189"
"Event1"    "FootBall"      "FootBall1"     "started"   "1554980082"

我需要选择查询来显示数据如下：

EVENT       EVENTNAME       EVENTACTION     STATUS      STARTTIME   RUNNINGTIME ENDTIME
"Event1"    "FootBall"      "FootBall0"     "success"   1554980085  NULL        1554980087
"Event1"    "TableTennis"   "TT0"           "running"   1554980086  1554980189  NULL 
"Event1"    "Chess"         "CHESS0"        "success"   1554980098  NULL        1554980100

我必须显示EVENT、EVENTNAME、EVENTACTION 和最新的STATUS 以及started、running 和success 的时间戳，如果时间不存在则应设置@987654330 @。

我使用了带有大小写的 SELECT 查询，但时间戳没有放在单个相关行中。

SELECT AE.EVENT,
AE.EVENTNAME,
AE.EVENTACTION,
AE.STATUS,
(case WHEN AE.STATUS='started' THEN AE.timestamp END) as starttime,
(case WHEN AE.STATUS='running' THEN AE.timestamp END) as runningtime,
(case WHEN AE.STATUS in ('success','failed') THEN AE.timestamp END) as endtime
FROM agentEvents AE 
ORDER by timestamp ASC

任何线索。

Answer 1

需要按事件聚合，然后取MAX的CASE表达式：

SELECT
    AE.EVENT,
    AE.EVENTNAME,
    AE.EVENTACTION,
    MAX(CASE WHEN AE.STATUS = 'started' THEN AE.timestamp END) AS starttime,
    MAX(CASE WHEN AE.STATUS = 'running' THEN AE.timestamp END) AS runningtime,
    MAX(CASE WHEN AE.STATUS IN ('success', 'failed') THEN AE.timestamp END) AS endtime
FROM agentEvents AE
GROUP BY
    AE.EVENT,
    AE.EVENTNAME,
    AE.EVENTACTION
ORDER BY
    MAX(CASE WHEN AE.STATUS = 'started' THEN AE.timestamp END);

请注意，单独按timestamp 列排序是没有意义的，因为聚合后它不再存在。所以，我改为按开始时间订购。选择STATUS列也没有意义，所以我把它去掉了。