有没有一种方法可以让函数连续运行，直到用户告诉它停止？

Question

我目前正在尝试在 Python 3 中为树莓派编写一个程序，以控制位于桌子上的一组线性致动器，这将改变腿的长度并允许桌面倾斜。桌子的一个特点是自动调平功能，以确保桌面始终保持水平，并且如果它检测到它不是通过从板载加速器中提取数据，它将自我纠正。自动级别功能工作得非常好，但是我很难在开和关条件下进行编程。理想情况下，在控制台中键入 a(1) 将调用 autolevel 函数并使其持续运行，直到键入 a(0) 将其停止。我设法通过键入 a(1) 来运行该函数，但是一旦接受该命令，程序就会停止侦听进一步的命令并无休止地循环。当前状态的代码发布在下面。

def a(n):
    while n== 1:
        acceleration = sense.get_accelerometer_raw()
        x = acceleration['x']
        y = acceleration['y']
        z = acceleration['z']
        
        x=round(x, 3)
        y=round(y, 3)
        z=round(z, 3)
        
        if x >0.00:
            GPIO.output(12,0)
            GPIO.output(13,1)#leg 1 retract
            GPIO.output(15,0)
            GPIO.output(29,1)#leg 2 retract
            GPIO.output(31,1)
            GPIO.output(32,0)#leg 3 extend
            GPIO.output(33,1)
            GPIO.output(36,0)#leg 4 extend
            sense.show_message('Correcting forward tilt')
            
        elif x <0.00:
            GPIO.output(12,1)
            GPIO.output(13,0)#leg 1 extend
            GPIO.output(15,1)
            GPIO.output(29,0)#leg 2 extend
            GPIO.output(31,0)
            GPIO.output(32,1)#leg 3 retract
            GPIO.output(33,0)
            GPIO.output(36,1)#leg 4 retract
            sense.show_message('Correcting rearward tilt')
            
        else:
            if y >0.00:
                GPIO.output(12,0)
                GPIO.output(13,1)#leg 1 retract
                GPIO.output(15,1)
                GPIO.output(29,0)#leg 2 extend
                GPIO.output(31,0)
                GPIO.output(32,1)#leg 3 retract
                GPIO.output(33,1)
                GPIO.output(36,0)#leg 4 extend
                sense.show_message('Correcting right side tilt')
            elif y <0.00:
                GPIO.output(12,1)
                GPIO.output(13,0)#leg 1 extend
                GPIO.output(15,0)
                GPIO.output(29,1)#leg 2 retract
                GPIO.output(31,1)
                GPIO.output(32,0)#leg 3 extend
                GPIO.output(33,0)
                GPIO.output(36,1)#leg 4 retract
                sense.show_message('Correcting left side tilt')
            else:
                sense.show_message("No tilt to correct")
                print ("Stand currently level, standing by for reactive adjustment.")

Answer 1

你可以使用多线程， 以下是如何将其合并到：

您将被要求输入值，在您的情况下将是“退出”关键字。 让我知道是否有效。

import threading 

flag=False
def a1(): 
    global flag
    a= flag
    #if(a==True):
    while (!a):
        acceleration = sense.get_accelerometer_raw()
        x = acceleration['x']
        y = acceleration['y']
        z = acceleration['z']
        #paste the rest of your code here
   
    
def loopBreak(): 
    """ 
    function to exit the loop
    """
    global flag
    inp=input("Enter value")
    if inp=="exit":
      flag =True


if __name__ == "__main__": 
    # creating thread 
    t1 = threading.Thread(target=a1) 
    t2 = threading.Thread(target=loopBreak) 
  
    # starting thread 1 
    t1.start() 
    # starting thread 2 
    t2.start() 
  
    # wait until thread 1 is completely executed 
    t1.join() 
    # wait until thread 2 is completely executed 
    t2.join() 
    print(flag)
    # both threads completely executed 
    print("Done!")