带有两个按钮和一个 LED 的 SR 闩锁 (Arduino)

Question

我的代码有什么问题？我不断得到

需要左值作为赋值的左操作数

我正在尝试用 2 个按钮构建一个 SR latch，如果按下两个按钮，LED 应该处于低电平。如果它们中的任何一个被按下，LED 应该能够一直亮着，直到它被另一个按钮重置

#include <arduinio.h>


const int buttonPin[] = {2,3};     // the number of the pushbutton pins
const int ledPin =  4;      // the number of the LED pin

// variables will change:
int buttonState1 = 0;         // variable for reading the pushbutton status
int buttonState2 = 0; 
void setup() {
  Serial.begin(9600);
  // initialize the LED pin as an output:
  pinMode(ledPin, OUTPUT);  
  digitalWrite(ledPin, LOW);  
  // initialize the pushbutton pin as an input:
  pinMode(2,INPUT);
  pinMode(3,INPUT);
}

void loop(){
 buttonState1 = digitalRead (2);
  buttonState2 = digitalRead (3);
  Serial.println(buttonState1);
  Serial.println(buttonState2);

  if (buttonState1 = 1 && buttonState2 = 0) {    
      // turn LED on:  
      digitalWrite(ledPin, HIGH);
    }
      else if (buttonState1 = 0 && buttonState2 = 1) {    
      // turn LED on:  
      digitalWrite(ledPin, HIGH);
    }
    else if (buttonState1 = 0 && buttonState2 = 0) {    
      // turn LED on:  
      digitalWrite(ledPin, HIGH);
    }
    else {    
      // turn LED on:  
      digitalWrite(ledPin, LOW);
    }
}

Answer 1

问题在于您在 if 条件中使用 = 而不是 ==。应该是这样的：

if (buttonState1 == 1 && buttonState2 == 0) {}