MS Access 将查询结果行透视到列中

Question

我是使用 MS-Access 报告的新手。我有一个查询返回员工时间表的结果，按月份和工资码分组。我想制作一份显示以下内容的报告

Employee	OT Shifts Jan	Regular Shifts Jan	OT Shifts Feb	Regular Shifts Feb
1234	1	1	2	1
5678	5	2	1	0

但是我的查询格式为：

Employee	Month	Shift	Paycode
1234	Jan	1	OT
1234	Jan	1	Regular
1234	Feb	2	OT
1234	Feb	1	Regular
5678	Jan	5	OT
5678	Jan	2	Regular
5678	Feb	1	OT
5678	Feb	0	Regular

是否可以有条件地告知报告上的字段引用特定的“Where 子句”，以便我可以随意移动字段，或者我是否需要修改我的查询才能做到这一点？

作为参考，我的查询代码是：

SELECT tblAssignedEmployees.EmployeeID, Format(Date_In,"yyyy-mm") AS [Month], Count(tblShift.Date_In) AS ShiftsPerEmployee, tblAssignedEmployees.PayCode
FROM tblShift INNER JOIN tblAssignedEmployees ON tblShift.ShiftNum = tblAssignedEmployees.ShiftNum
GROUP BY tblAssignedEmployees.EmployeeID, Format(Date_In,"yyyy-mm"), tblAssignedEmployees.PayCode;

Answer 1

考虑条件聚合：

SELECT e.EmployeeID
     , SUM(IIF(MONTH(s.Date_In) = 1 AND e.PayCode = 'OT', 1, 0) AS [OT Shifts Jan]
     , SUM(IIF(MONTH(s.Date_In) = 1 AND e.PayCode = 'Regular', 1, 0) AS [Regular Shifts Jan]
     , SUM(IIF(MONTH(s.Date_In) = 2 AND e.PayCode = 'OT', 1, 0) AS [OT Shifts Feb]
     , SUM(IIF(MONTH(s.Date_In) = 2 AND e.PayCode = 'Regular', 1, 0) AS [Regular Shifts Feb]
FROM tblShift s
INNER JOIN tblAssignedEmployees e
   ON s.ShiftNum = e.ShiftNum
GROUP BY e.EmployeeID

如果没有IIF，则更短，将 True 条件相加但乘以 -1，因为 Access 将 True 视为 -1 而 False 视为 0。

SELECT e.EmployeeID
     , SUM(MONTH(s.Date_In) = 1 AND e.PayCode = 'OT') * -1 AS [OT Shifts Jan]
     , SUM(MONTH(s.Date_In) = 1 AND e.PayCode = 'Regular') * -1 AS [Regular Shifts Jan]
     , SUM(MONTH(s.Date_In) = 2 AND e.PayCode = 'OT') * -1 AS [OT Shifts Feb]
     , SUM(MONTH(s.Date_In) = 2 AND e.PayCode = 'Regular') * -1 AS [Regular Shifts Feb]
FROM tblShift s
INNER JOIN tblAssignedEmployees e
   ON s.ShiftNum = e.ShiftNum
GROUP BY e.EmployeeID