【发布时间】:2020-09-14 23:47:47
【问题描述】:
我正在尝试使用minio 作为本地 S3 服务器。我正在关注这个article
我下载了密钥和证书文件。 我添加了环境参数:
set MINIO_KMS_KES_ENDPOINT=https://play.min.io:7373
set MINIO_KMS_KES_KEY_FILE=D:\KMS\root.key
set MINIO_KMS_KES_CERT_FILE=D:\KMS\root.cert
set MINIO_KMS_KES_KEY_NAME=my-minio-key
我启动了minio服务器:D:\>minio.exe server D:\Photos
启动后记录:
Endpoint: http://169.254.182.253:9000 http://169.254.47.198:9000 http://172.17.39.193:9000 http://192.168.0.191:9000 http://169.254.103.105:9000 http://169.254.209.102:9000 http://169.254.136.71:9000 http://127.0.0.1:9000
AccessKey: minioadmin
SecretKey: minioadmin
Browser Access:
http://169.254.182.253:9000 http://169.254.47.198:9000 http://172.17.39.193:9000 http://192.168.0.191:9000 http://169.254.103.105:9000 http://169.254.209.102:9000 http://169.254.136.71:9000 http://127.0.0.1:9000
Command-line Access: https://docs.min.io/docs/minio-client-quickstart-guide
$ mc.exe alias set myminio http://169.254.182.253:9000 minioadmin minioadmin
Object API (Amazon S3 compatible):
Go: https://docs.min.io/docs/golang-client-quickstart-guide
Java: https://docs.min.io/docs/java-client-quickstart-guide
Python: https://docs.min.io/docs/python-client-quickstart-guide
JavaScript: https://docs.min.io/docs/javascript-client-quickstart-guide
.NET: https://docs.min.io/docs/dotnet-client-quickstart-guide
Detected default credentials 'minioadmin:minioadmin', please change the credentials immediately using 'MINIO_ACCESS_KEY' and 'MINIO_SECRET_KEY'
我在浏览器中打开 UI:http://localhost:9000/minio/mybacket/ 我尝试上传 jpg 文件并出现异常:
<?xml version="1.0" encoding="UTF-8"?> <Error><Code>InternalError</Code><Message>We encountered an internal error, please try again.</Message><Key>Completed.jpg</Key><BucketName>mybacket</BucketName><Resource>/minio/upload/mybacket/Completed.jpg</Resource><RequestId>1634A6E5663C9D70</RequestId><HostId>4a46a947-6473-4d53-bbb3-a4f908d444ce</HostId></Error>
我在 minio 控制台中遇到了这个异常:
Error: Post "https://play.min.io:7373/v1/key/generate/my-minio-key": x509: certificate signed by unknown authority
3: cmd\api-errors.go:1961:cmd.toAPIErrorCode()
2: cmd\api-errors.go:1986:cmd.toAPIError()
1: cmd\web-handlers.go:1116:cmd.(*webAPIHandlers).Upload()
【问题讨论】: