【发布时间】:2012-11-11 10:22:30
【问题描述】:
; defining the procedure char_toupper to convert a lower case character to upper case
(define char_toupper (lambda (myChar)
; defining x as the ASCII value of myChar
(define x (char->integer myChar))
; defining y as x-32
(define y (- x 32))
; if statement for while x is less than 91 (already uppercase)
(if (< x 91)
; if it is already uppercase, just display it
(display myChar)
; otherwise, if x is greater than 96 (lowercase)
(if (> x 96)
; then display the character equivalent to the ASCII value given by y
(display (integer->char y))))))
(define string_toupper (lambda (myString newString i)
(if (< i (string-length myString))
(string_toupper myString (string-append newString (char_toupper (string-ref myString i))) (+ 1 i)))
(display newString)))
(string_toupper (read) "" 0)
这会将每个字符转换为大写,并显示它。但我不断收到错误,我可以找到它。任何帮助。谢谢
【问题讨论】:
-
你不断得到的错误是?
-
字符串长度:预期违反合同:字符串?
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read 不一定返回字符串。它返回一个值,但该值可能是一个字符串、一个符号、一个数字、一个列表,或者......取决于用户输入的内容。所以你可能想使用 read-line 代替:@ 987654321@
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还有char_toupper函数实际上返回void...