如何在 xcode 6 中构建 32 位和 64 位的单个二进制文件

Question

我已关注this 堆栈溢出解决方案，但即使我收到警告以下内容。

Missing 64 bit support.Starting February 1, 2015, new iOS apps uploaded to the App Store
must include 64-bit support and be built with the iOS 8 SDK, included in Xcode 6 or later.
To enable 64-bit in your project, we recommend using the default Xcode build setting of 
“Standard architectures” to build a single binary with both 32-bit and 64-bit code.

我选择了

 Project - Target - Build settings - Architectures - Standard Architectures(armv7,arm64). 

尽管我得到了警告。请帮帮我。在此先感谢。

Answer 1

有同样的问题。似乎将“arm64”添加到有效架构（也在构建设置下）解决了它。

Answer 2

也许你想看看这个： https://developer.apple.com/library/IOs/documentation/General/Conceptual/CocoaTouch64BitGuide/ConvertingYourAppto64-Bit/ConvertingYourAppto64-Bit.html