如何在不删除变量的情况下阻止变量被引用？

Question

因此，在我进行编程时，我创建了一个变量 (rYouTube)，用于存储识别器。我创建了另一个名为 rGoogle 的变量，其中存储了另一个识别器。唯一的问题是，每次我选择 Google 而不是 YouTube 时，我都会不断收到错误消息“UnboundLocalError: local variable 'rYouTube' referenced before assignment”，因为我的程序的工作方式是你选择一个然后程序继续运行（如果你选择了 YouTube ，你可以看看东西，如果你选择谷歌，你可以查东西）

所以我已经尝试将变量值作为占位符提供，但由于这些变量是音频变量，它不起作用。

                print("Would you like to Direct Search?")
            rYouTube = sr.Recognizer()
            with sr.Microphone() as source:
                        rYouTube.adjust_for_ambient_noise(source)
                        YTaudio = rYouTube.listen(source)
                        print("LOADING...")
                        time.sleep(1)

        try:
                DirectYTRecognized = rYouTube.recognize_google(YTaudio)
                print(DirectYTRecognized)
        except sr.UnknownValueError:
                print("Google Speech Recognition could not understand audio")
        except sr.RequestError as e:
                print("Could not request results from Google Speech Recognition service; {0}".format(e))


        if "yes" in DirectYTRecognized:
                print("What do you want to watch?")
        SearchYouTube = sr.Recognizer()
        with sr.Microphone() as source:
                        SearchYouTube.adjust_for_ambient_noise(source)
                        YTSearchAudio = SearchYouTube.listen(source)
                        print("LOADING...")
                        time.sleep(1)

        try:
                FinalSearchYTAudio = SearchYouTube.recognize_google(YTSearchAudio)
                print(FinalSearchYTAudio)
            DirectYT = "https://youtube.com/results?search_query=" + FinalSearchYTAudio
            webbrowser.open_new(DirectYT)
        except sr.UnknownValueError:
                print("Google Speech Recognition could not understand audio")
        except sr.RequestError as e:
                print("Could not request results from Google Speech Recognition service; {0}".format(e))

#END OF YT DIRECT SEARCH-------------------------------------

#GOOGLE DIRECT SEARCH---------------------------------------
        if "Google" in recognized:
                print("Would you like to Direct Search?")
            rGoogle = sr.Recognizer()
            with sr.Microphone() as source:
                        rGoogle.adjust_for_ambient_noise(source)
                        GoogleAudio = rGoogle.listen(source)
                        print("LOADING...")
                        time.sleep(1)

        try:
                DirectGoogleRecognized = rGoogle.recognize_google(GoogleAudio)
                print(DirectGoogleRecognized)
        except sr.UnknownValueError:
                print("Google Speech Recognition could not understand audio")
        except sr.RequestError as e:
                print("Could not request results from Google Speech Recognition service; {0}".format(e))


        if "yes" in DirectGoogleRecognized:
                print("What do you want to look up?")
        SearchGoogle = sr.Recognizer()
        with sr.Microphone() as source:
                        SearchGoogle.adjust_for_ambient_noise(source)
                        GoogleSearchAudio = SearchGoogle.listen(source)
                        print("LOADING...")
                        time.sleep(1)

        try:
                FinalSearchGooleAudio = SearchGoogle.recognize_google(YTSearchAudio)
                print(FinalSearchGoogleAudio)
            DirectGoogle = "https://youtube.com/results?search_query=" + FinalSearchGoogleAudio
            webbrowser.open_new(DirectGoogle)
        except sr.UnknownValueError:
                print("Google Speech Recognition could not understand audio")
        except sr.RequestError as e:
                print("Could not request results from Google Speech Recognition service; {0}".format(e))

我希望程序继续工作，但它停止并显示：“UnboundLocalError: local variable 'rYouTube' referenced before assignment”

Answer 1

你的 Try except 语句不应该尽可能地缩进，它们应该缩进到与它们之前的 with 相同的级别。 （这似乎是您发布的代码及其显示的格式的问题。