sql如何实现这个查看表

Question

我想从下表中实现这个视图。

(a) 我想得到两列，其中 group1 具有不同的值，其中 c3= yes 和 group2，其中它根据 group1 具有 sum(c2)。

(b) 第 3 组是根据 group1 的 sum(c4) 和 group4 是根据第 1 组的 sum(c5) 。怎么做？

c1   |   c2   | c3   | c4 | c5
--------------|---------------
A    |   2    |yes   | 1   | 2
B    |   1    |yes   | 2   | 1
A    |   2    |yes   | 1   | 2
B    |   1    |yes   | 2   | 1
C    |   2    |no    | 4   | 4
C    |   1    |no    | 4   | 4




result :


group1 | group2| group3| group4
--------------------------------
A      | 4     | 2     | 4
B      | 2     | 4     | 2

a 部分已通过此查询解决

SELECT c1 as group1, SUM(c2) as group2 FROM table 
WHERE c3="yes"
GROUP BY c1

由 Theo Babilon 回答

但是如何解决 b 部分并获得完整的视图？

Answer 1

SELECT c1 as group1, SUM(c2) as group2, SUM(c4) as group3, SUM(c5) as group4
FROM table
WHERE c3 = "yes"
GROUP BY c1

Answer 2

使用这个查询

SELECT c1 as group1, SUM(c2) as group2, SUM(c4) as group3, SUM(c5) as group4
FROM table
WHERE c2 = 'yes'
GROUP BY c1