与对象的属性之一匹配后如何打印对象的属性

Question

我想匹配对象的属性值之一，如果它匹配该属性，我需要打印该对象的所有其他属性。 我正在尝试匹配 firstName 属性并打印其剩余部分。

这里是代码

      var friends=new Object();
  friends.steve={
  firstName:"Steve",
  lastName:"smith",
  number:"8861785484",
  address:['rajajinagar','bangalore','560010']
  };

friends.bill={
firstName:"Bill",
lastName:"gates",
number:"9845378136",
address:['shivajinagar','bangalore','560018']
};


var search=function(name){
    for(firstName in friends){
        if(friends[name].firtstName===name){
            console.log(friends[name]);
            return (friends[name]);
            
            }
        
        
        }
    
    }
 search("steve");

输出应该是 "steve" 对象的所有属性，例如.. firstName、lastName、number 和 address

Answer 1

让朋友成为对象数组，而不是对象对象，然后试试这个：

for(var i = 0;i<friends.length;i++){
    if(friends[i].firstName===name){
        console.log(friends[i]);
        return friends[i];
    }
}

Answer 2

我愿意这样做；

var friends = new Object(),
  getDetail = n => friends[n.toLowerCase()];
friends.steve={
  firstName:"Steve",
  lastName:"smith",
  number:"8861785484",
  address:['rajajinagar','bangalore','560010']
  };

friends.bill={
  firstName:"Bill",
  lastName:"gates",
  number:"9845378136",
  address:['shivajinagar','bangalore','560018']
};
console.log(getDetail("Steve"));

可能会这样做；

Answer 3

您可以在属性上使用Array#forEach 进行迭代（使用Object.keys）并检查firstName 是否等于name。此提案查找所有 steve。

变量k表示对象的属性名，如'steve'或'bill'。

var friends = { steve: { firstName: "Steve", lastName: "smith", number: "8861785484", address: ['rajajinagar', 'bangalore', '560010'] }, bill: { firstName: "Bill", lastName: "gates", number: "9845378136", address: ['shivajinagar', 'bangalore', '560018'] } },
    search = function (name) {
        Object.keys(friends).forEach(function (k) {
            if (friends[k].firstName.toLowerCase() === name.toLowerCase()) {
                console.log(friends[k]);
            }
        });
    };

search("steve");

带有for ... in 循环的提案。

var friends = { steve: { firstName: "Steve", lastName: "smith", number: "8861785484", address: ['rajajinagar', 'bangalore', '560010'] }, bill: { firstName: "Bill", lastName: "gates", number: "9845378136", address: ['shivajinagar', 'bangalore', '560018'] } },
    search = function (name) {
        for (k in friends) {
            if (friends[k].firstName.toLowerCase() === name.toLowerCase()) {
                console.log(friends[k]);
            }
        };
    };

search("steve");