@SQL 使用单列我需要得到下面提到的输出，如下所示[重复]答案

【问题标题】：@SQL With single column i need to get below mentioned output like below [duplicate]@SQL 使用单列我需要得到下面提到的输出，如下所示[重复]
【发布时间】：2015-12-22 22:32:42
【问题描述】：

我在表格中有以下数据

**TEAM NAME**
Germany
Holland 
Scotland
Brazil

我期望数据如下所示，顺序相同，请帮助

**ScheduledMatches**
Germany VS Holland
Germany VS Scoltland
Germany VS Brazil
Holland VS Scoltland
Holland VS Brazil
Scoltland VS Brazil

谢谢维杰萨加尔

【问题讨论】：

你有没有尝试过？

标签： sql sql-server

【解决方案1】：

您可以先计算每个团队的ROW_NUMBER，然后根据计算出的rn 使用< 的self join：

CREATE TABLE #teams(name VARCHAR(100));

INSERT INTO #teams(name)
VALUES('Germany'), ('Holland'), ('Scotland'), ('Brazil');

;WITH cte AS
(
  SELECT *, rn = ROW_NUMBER() OVER (ORDER BY (SELECT 1))
  FROM #teams
)
SELECT CONCAT(c1.name, ' vs ',  c2.name) AS result  
FROM cte c1
JOIN cte c2 
  ON c1.rn < c2.rn
-- ORDER BY result;

LiveDemo

CONCAT 可从SQL Server 2012+ 获得，如果您的版本较低，请使用+ 连接字符串。

【讨论】：

【解决方案2】：

DECLARE @t TABLE (Team VARCHAR(100))
INSERT INTO @t (Team)
VALUES
    ('Germany'),
    ('Holland'), 
    ('Scotland'),
    ('Brazil')

;WITH cte AS 
(
    SELECT *, RowNum = ROW_NUMBER() OVER (ORDER BY 1/0)
    FROM @t   
)
SELECT t2.Team + ' vs ' + t1.Team
FROM cte t1
JOIN cte t2 ON t1.RowNum > t2.RowNum

输出 -

---------------------------
Germany vs Holland
Germany vs Scotland
Germany vs Brazil
Holland vs Scotland
Holland vs Brazil
Scotland vs Brazil

【讨论】：

【解决方案3】：

下面的代码对你有帮助！！！

SELECT
    a.M +' VS '+ b.M AS [**ScheduledMatches**]
FROM (
    SELECT *, ROW_NUMBER() OVER (PARTITION BY 1 order by 1/0) AS no
    FROM (
        VALUES ('Germany'), ('Holland'), ('Scotland'), ('Brazil')
    ) t (m)
) a
JOIN (
    SELECT *, ROW_NUMBER() OVER (PARTITION BY 1 order by 1/0) AS no
    FROM (
        VALUES ('Germany'), ('Holland'), ('Scotland'), ('Brazil')
    ) t (m)
) b ON a.no < b.no

输出：

 **ScheduledMatches**
Germany VS Holland
Germany VS Scotland
Germany VS Brazil
Holland VS Scotland
Holland VS Brazil
Scotland VS Brazil

【讨论】：