使用脚本和 XML Feed 暂停 Google Adwords 中的广告组

Question

我正在尝试编写一个脚本来暂停基于 XML（Google Merchant XML）中的 AVAILABILITY 字段的广告组。

我有一个商家 XML，并且想使用 XML 中的 ID（该 ID 是在广告组名称中使用的算法）和 AVAILABILITY（有货、缺货、预购）来暂停我的广告系列中的广告组。

我尝试修改示例I had found here，使用广告组代替广告系列，但我认为错误在于脚本尝试读取 XML 时。 在下面的行中，我收到错误：“TypeError：无法调用 null 的方法“getValue”。（第 16 行）”

var id = entries[i].getChild('g:id').getValue();
var availability = entries[i].getChild('g:availability').getValue();

我的 XML 是这样的：

<rss xmlns:g="http://base.google.com/ns/1.0" version="2.0">
    <channel>
        <item>
            <title>
                <![CDATA[ Far Cry 4: Overrun ]]>
            </title>
            <link>https://www.nuuvem.com/item/far-cry-4-overrun</link>
            <description>
                <![CDATA[
Neste novo conteúdo para Far Cry 4, enquanto a guerra sem trégua por Kyrat continua, os jogadores assumirão o papel dos Rakshasa e do Caminho Dourado para manter locais que dão pontos no mapa da batalha.
]]>
            </description>
            <g:availability>in stock</g:availability>
            <g:price currency="BRL">8.99</g:price>
            <g:image_link> http://dskhvldhwok3h.cloudfront.net/image/upload/t_boxshot_big/v1/products/557dbcb269702d0a9c490801/boxshots/ynhjodwlnmur0crkiaxp.jpg </g:image_link>
            <g:product_type>
                <![CDATA[ Ação ]]>
            </g:product_type>
            <g:google_product_category>Software > Video Game Software > Computer Games</g:google_product_category>
            <g:condition>new</g:condition>
            <g:identifier_exists>FALSE</g:identifier_exists>
            <g:id>2668</g:id>
        </item>

我的脚本现在如下所示：

function main() {
    // Load an XML file:
    var xmlURL = "XML URL HERE";
    var xmlFile = UrlFetchApp.fetch(xmlURL);
    // Parse the XML file:
    var document = XmlService.parse(xmlFile);
    var root = document.getRootElement();
    // Go through all children of <deepdive_pages>:
    var entries = document.getRootElement().getChildren();
    for (var i = 0; i < entries.length; i++) {
        //for (var i = 0; i < 10; i++) {
        var id = entries[i].getChild('g:id').getValue();
        var availability = entries[i].getChild('g:availability').getValue();
        // If company_root_id has 0 jobs 
        if (availability == "out of stock") {
            var adGroupIterator = AdWordsApp.adGroups().withCondition('Name CONTAINS "| ' + id + ' |"').get(); // Find all campaigns with the company name
            while (adGroupIterator.hasNext()) { // Go over all campaings with company id in the name
                var adgroup = adGroupIterator.next();
                if (adgroup.isEnabled()) { // If campaign is enables, pause it
                    adgroup.pause();
                    Logger.log("adgroup " + adgroup.getName() + " was paused.");
                }
            }
        }
        // If company_root_id has MORE than 0 jobs 
        else {
            var adGroupIterator = AdWordsApp.adGroups().withCondition('Name CONTAINS "| ' + id + ' |"').get(); // Find all campaigns with the company name
            while (adGroupIterator.hasNext()) { // Go over all campaings with company id in the name
                var adgroup = adGroupIterator.next();
                if (adgroup.isPaused()) { // If campaign is paused, enable it
                    adgroup.enable();
                    Logger.log("adgroup " + adgroup.getName() + " was enabled.");
                }
            }
        } // End If Else
    }
}

非常感谢您的帮助！

Answer 1

在这篇文章中得到了 Calin 的帮助：https://www.en.advertisercommunity.com/t5/Advanced-Features/Script-to-pause-Adggroups-based-in-information-from-a-Merchant/m-p/1024590#

我解决了我的问题。

为了正确读取 XML，我使用了：

// Load an XML file:
 var xmlURL = "XML_MERCHANT_URL_HERE";
 var xmlFile = UrlFetchApp.fetch(xmlURL);

 // Parse the XML file:
 var document = XmlService.parse(xmlFile);
 var ns = XmlService.getNamespace("http://base.google.com/ns/1.0");   
 var rss = document.getRootElement().getChildren(); //root element is <rss>; it's children are actually only one, <channel>
 var entries = rss[0].getChildren('item'); //getting all 'item' children of the first rss element, <channel>

 // Go through all children of <deepdive_pages>:
 Logger.log(entries.length);

 for (var i = 0; i < entries.length; i++) {

 var id = entries[i].getChild('id',ns).getText();

 var availability = entries[i].getChild('availability',ns).getText();

//Logger.log("ID: "+id+", Availability: "+availability);

在我没有声明 XML 命名空间之前我使用的是getchild，但在这种情况下我需要使用getChildren。