Sed：从 txt 文件中删除行？ [复制]

Question

如何从文本文件中删除“name['todo']['remove'] = 3456”行？

[test.txt]
name['myname']['test'] = 12
name['todo']['remove'] = 3456
name['todo']['remove']['inspection'] = 34

我目前的方法没有按预期工作。该行仍在我的文件中。

sed -i "name\['todo'\]\['remove'\]" test.txt

错误信息是“sed: -e expression #1, char 2: extra characters after command”

Answer 1

一个简单的 grep -vF 在这里可以正常工作，它使用 fixed string 进行匹配，而无需转义特殊的正则表达式字符：

grep -ivF "name['todo']['remove'] " file

[test.txt]
name['myname']['test'] = 12
name['todo']['remove']['inspection'] = 34

Answer 2

你可以使用

sed -i "/name\['todo']\['remove'] =/d" test.txt

请注意，该模式用 / 正则表达式分隔符包裹，d 表示匹配的行将被删除。

查看online demo：

s="[test.txt]
name['myname']['test'] = 12
name['todo']['remove'] = 3456
name['todo']['remove']['inspection'] = 34"
sed "/name\['todo']\['remove'] =/d" <<< "$s"

屈服

[test.txt]
name['myname']['test'] = 12
name['todo']['remove']['inspection'] = 34

如果你想确保只匹配= 之后的整行数字，你可以使用"/^name\['todo']\['remove'] = [0-9]*$/d" 命令和sed。