【发布时间】:2018-08-22 04:59:33
【问题描述】:
我想使用 sed 或 gawk/awk 命令来查找正则表达式:
TRAFFIC
并将其与以下 unix 命令或类似命令结合使用,使 sysdate 减去一天:
date "--date=${dataset_date} -${date_diff} 1 day" +%d%b%Y
然后删除 regexp 和 sysdate 之间的所有行减去一天。
文件输入示例:
TYPE = REGIONAL (keep)
TRAFFIC AND LOGISTICS (keep)
(delete)
DATE (delete)
01AUG18 (delete)
TIME TRA NDFV (delete)
00:00-00:15 0.00 0 (delete)
00:15-00:30 0.00 0 (delete)
00:30-00:45 0.00 1 (delete)
DATE (delete)
02AUG18 (keep - sysdate minus one day)
TIME TRA NDFV (keep)
00:00-00:15 0.00 2 (keep)
00:15-00:30 0.00 0 (keep)
00:30-00:45 0.00 0 (keep)
00:45-01:00 0.00 0 (keep)
文件输出示例:
TYPE = REGIONAL
TRAFFIC AND LOGISTICS
02AUG18
TIME TRA NDFV
00:00-00:15 0.00 2
00:15-00:30 0.00 0
00:30-00:45 0.00 0
00:45-01:00 0.00 0
在这种情况下,02AUG18 将是 sysdate 减去一天。通常在正则表达式和 sysdate 之间会有更多的行要删除。是否可以组合如下命令:
sed '/TRAFFIC/,/ [sysdate minus one day] /d'
【问题讨论】: