使用 POST 方法将文件上传到 file.io

Question

我在 SO 上找到了一个链接，可能会在此查询中有所不同 Upload a Picture to file.io (HTTP Post) in VBA 此链接中的代码

Sub UploadFilesUsingVBAORIGINAL()
     'this proc will upload below files to https://file.io/
          '  png, jpg, txt

        Dim fileFullPath As String
        fileFullPath = ThisWorkbook.Path & "\Sample.txt"

        POST_multipart_form_dataO fileFullPath
    End Sub

Private Function GetGUID() As String
    ' Generate uuid version 4 using VBA
    GetGUID = WorksheetFunction.Concat(WorksheetFunction.Dec2Hex(WorksheetFunction.RandBetween(0, 4294967295#), 8), "-", WorksheetFunction.Dec2Hex(WorksheetFunction.RandBetween(0, 65535), 4), "-", WorksheetFunction.Dec2Hex(WorksheetFunction.RandBetween(16384, 20479), 4), "-", WorksheetFunction.Dec2Hex(WorksheetFunction.RandBetween(32768, 49151), 4), "-", WorksheetFunction.Dec2Hex(WorksheetFunction.RandBetween(0, 65535), 4), WorksheetFunction.Dec2Hex(WorksheetFunction.RandBetween(0, 4294967295#), 8))

End Function

Private Function GetFileSize(fileFullPath As String) As Long

    Dim lngFSize As Long, lngDSize As Long
    Dim oFO As Object, OFS As Object

    lngFSize = 0
    Set OFS = CreateObject("Scripting.FileSystemObject")

    If OFS.FileExists(fileFullPath) Then
        Set oFO = OFS.GetFile(fileFullPath)
        GetFileSize = oFO.Size
    Else
        GetFileSize = 0
    End If

    Set oFO = Nothing
    Set OFS = Nothing
End Function



Private Function ReadBinary(strFilePath As String)
    Dim ado As Object, bytFile
    Set ado = CreateObject("ADODB.Stream")
    ado.Type = 1
    ado.Open
    ado.LoadFromFile strFilePath
    bytFile = ado.Read
    ado.Close

    ReadBinary = bytFile

    Set ado = Nothing
End Function


Private Function toArray(str)
    Dim ado As Object
     Set ado = CreateObject("ADODB.Stream")
     ado.Type = 2
     ado.Charset = "_autodetect"
     ado.Open
     ado.WriteText (str)
     ado.Position = 0
     ado.Type = 1
     toArray = ado.Read()
     Set ado = Nothing
End Function


Sub POST_multipart_form_dataO(filePath As String)

    Dim oFields As Object, ado As Object
    Dim sBoundary As String, sPayLoad As String, GUID As String
    Dim fileType As String, fileExtn As String, fileName As String
    Dim sName As Variant

    fileName = Right(filePath, Len(filePath) - InStrRev(filePath, "\"))
    fileExtn = Right(filePath, Len(fileName) - InStrRev(fileName, "."))

    Select Case fileExtn
     Case "png"
        fileType = "image/png"
     Case "jpg"
        fileType = "image/jpeg"
     Case "txt"
        fileType = "text/plain"
    End Select

    Set oFields = CreateObject("Scripting.Dictionary")
    With oFields
        .Add "qquuid", LCase(GetGUID)
        .Add "qqtotalfilesize", GetFileSize(filePath)
    End With

    sBoundary = String(27, "-") & "7e234f1f1d0654"
    sPayLoad = ""
    For Each sName In oFields
        sPayLoad = sPayLoad & "--" & sBoundary & vbCrLf
        sPayLoad = sPayLoad & "Content-Disposition: form-data; name=""" & sName & """" & vbCrLf & vbCrLf
        sPayLoad = sPayLoad & oFields(sName) & vbCrLf
    Next

    sPayLoad = sPayLoad & "--" & sBoundary & vbCrLf
    sPayLoad = sPayLoad & "Content-Disposition: form-data; name=""file""; " & "filename=""" & fileName & """" & vbCrLf
    sPayLoad = sPayLoad & "Content-Type: " & fileType & vbCrLf & vbCrLf & vbCrLf & vbCrLf & vbCrLf



     sPayLoad = sPayLoad & "--" & sBoundary & "--"


      Set ado = CreateObject("ADODB.Stream")
      ado.Type = 1
      ado.Open
      ado.Write toArray(sPayLoad)
      ado.Write ReadBinary(filePath)
      ado.Position = 0

    With CreateObject("MSXML2.ServerXMLHTTP")
        .Open "POST", "https://file.io", False
        .setRequestHeader "Content-Type", "multipart/form-data; boundary=" & sBoundary
        .send (ado.Read())
        Debug.Print .responseText
    End With

End Sub

任何人都可以试用此代码，因为该网站是免费的。当我运行代码时，我在即时窗口中获得了“成功”，并获得了上传文件的链接。 这似乎没有问题，但是当获取链接并将其放入浏览器时，我得到了 404 Page not found

我尝试手动上传相同的文件，它运行良好，没有任何问题，因为我从这个手动步骤获得的链接

有什么帮助吗？

也发在这里 https://chandoo.org/forum/threads/upload-file-to-file-io-using-post-method.43925/

Answer 1

在我看来，最终边界位于错误的位置，即文件内容之前。试试

Sub UploadToIO()

    Const PATH = "c:\tmp\"
    Const FILENAME = "testimage.png"
    Const CONTENT = "image/png"
    Const URL = "https://file.io"
    
    ' generate boundary
    Dim BOUNDARY, s As String, n As Integer
    For n = 1 To 16: s = s & Chr(65 + Int(Rnd * 25)): Next
    BOUNDARY = s & CDbl(Now)
    
    Dim part As String, ado As Object
    part = "--" & BOUNDARY & vbCrLf
    part = part & "Content-Disposition: form-data; name=""file""; filename=""" & FILENAME & """" & vbCrLf
    part = part & "Content-Type: " & CONTENT & vbCrLf & vbCrLf
           
    ' read file into image
    Dim image
    Set ado = CreateObject("ADODB.Stream")
    ado.Type = 1 'binary
    ado.Open
    ado.LoadFromFile PATH & FILENAME
    ado.Position = 0
    image = ado.read
    ado.Close
        
    ' combine part, image , end
    ado.Open
    ado.Position = 0
    ado.Type = 1 ' binary
    ado.Write ToBytes(part)
    ado.Write image
    ado.Write ToBytes(vbCrLf & "--" & BOUNDARY & "--")
    ado.Position = 0
    'ado.savetofile "c:\tmp\debug.bin", 2 ' overwrite
    
    ' send request
    With CreateObject("MSXML2.ServerXMLHTTP")
        .Open "POST", URL, False
        .setRequestHeader "Content-Type", "multipart/form-data; boundary=" & BOUNDARY
        .send ado.read
        Debug.Print .responseText
    End With

    MsgBox "File: " & PATH & FILENAME & vbCrLf & _
           "Boundary: " & BOUNDARY, vbInformation, "Uploaded to " & URL

End Sub

Function ToBytes(str As String) As Variant

    Dim ado As Object
    Set ado = CreateObject("ADODB.Stream")
    ado.Open
    ado.Type = 2 ' text
    ado.Charset = "_autodetect"
    ado.WriteText str
    ado.Position = 0
    ado.Type = 1
    ToBytes = ado.read
    ado.Close

End Function