【发布时间】:2016-05-12 12:46:39
【问题描述】:
我正在尝试将 Haversine 公式实现到 excel 函数中。它看起来像这样:
Public Function Haversine(Lat1 As Variant, Lon1 As Variant, Lat2 As Variant, Lon2 As Variant)
Dim R As Integer, dlon As Variant, dlat As Variant, Rad1 As Variant
Dim a As Variant, c As Variant, d As Variant, Rad2 As Variant
R = 6371
dlon = Excel.WorksheetFunction.Radians(Lon2 - Lon1)
dlat = Excel.WorksheetFunction.Radians(Lat2 - Lat1)
Rad1 = Excel.WorksheetFunction.Radians(Lat1)
Rad2 = Excel.WorksheetFunction.Radians(Lat2)
a = Sin(dlat / 2) * Sin(dlat / 2) + Cos(Rad1) * Cos(Rad2) * Sin(dlon / 2) * Sin(dlon / 2)
c = 2 * Excel.WorksheetFunction.Atan2(Sqr(a), Sqr(1 - a))
d = R * c
Haversine = d
End Function
但是当我测试它时,我得到了错误的距离......我不明白为什么。对于本主题中使用的坐标:Function to calculate distance between two coordinates shows wrong 我得到 20013,44 作为输出。有人知道这里有什么问题吗?找不到我的错误...
【问题讨论】:
-
只是一个问题:为什么选择“Variant”作为数据类型,而不是“double”?其次,您是否已经尝试使用 Excel 公式为此制作一个简单的 Excel 文件?这样可以更容易理解可能出了什么问题。
标签: excel vba formula haversine