有没有办法在Javascript中组合对象答案

【问题标题】：Is there a ways to combine objects in Javascript有没有办法在Javascript中组合对象
【发布时间】：2017-10-18 23:15:58
【问题描述】：

我正在用 Javascript 进行一些数据清理，我想知道是否有一种方法可以根据公共 ID 组合对象。

鉴于以下情况：

{"subject":"Hadji Singh","predicate":"nameOfUser","id":"3f540200-58b9-40a5-91c2-faafec75216f"}
{"subject":"Race Roger Bannon","predicate":"nameOfUser","id":"41376a49-34ee-4ed8-b5f5-3f8c92b107f8"}
{"subject":"Jessie Bannon","predicate":"nameOfUser","id":"9575cf33-8992-4763-81bb-fc640ffa3545"}
{"subject":"Adventurer","predicate":"departmentOfUser","id":"3f540200-58b9-40a5-91c2-faafec75216f"}
{"subject":"Bodyguard","predicate":"departmentOfUser","id":"41376a49-34ee-4ed8-b5f5-3f8c92b107f8"}
{"subject":"Adventurer","predicate":"departmentOfUser","id":"9575cf33-8992-4763-81bb-fc640ffa3545"}

有没有办法把它变成这样的东西？

[{id:3f540200-58b9-40a5-91c2-faafec75216f, name:Hadji Singh, department:Adventurer},
{id:9575cf33-8992-4763-81bb-fc640ffa3545, name:Jessie Bannon, department:Adventurer},
{id:41376a49-34ee-4ed8-b5f5-3f8c92b107f8, name:Race Bannon, department:Bodyguard}]

我正在考虑两个 for 循环（也许）和很多 if 循环，但也许我缺少某些方法。

我正在使用 node.js，如果这意味着什么。也许有一个模块可以提供帮助？

谢谢。

【问题讨论】：

请提供尝试过的解决方案，为什么它们不起作用，以及预期的结果。这真的会帮助我们找出你的代码的问题。谢谢！
使用id 作为HashMap 键并执行递归Object.assigns。不过，您必须设置优先规则。请提供更多详细信息，并可能进行一些尝试。
使用下划线 - stackoverflow.com/questions/19480008/…

标签： javascript

【解决方案1】：

使用数组的reduce方法：

let a = [{"subject":"Hadji Singh","predicate":"nameOfUser","id":"3f540200-58b9-40a5-91c2-faafec75216f"},
{"subject":"Race Roger Bannon","predicate":"nameOfUser","id":"41376a49-34ee-4ed8-b5f5-3f8c92b107f8"},
{"subject":"Jessie Bannon","predicate":"nameOfUser","id":"9575cf33-8992-4763-81bb-fc640ffa3545"},
{"subject":"Adventurer","predicate":"departmentOfUser","id":"3f540200-58b9-40a5-91c2-faafec75216f"},
{"subject":"Bodyguard","predicate":"departmentOfUser","id":"41376a49-34ee-4ed8-b5f5-3f8c92b107f8"},
{"subject":"Adventurer","predicate":"departmentOfUser","id":"9575cf33-8992-4763-81bb-fc640ffa3545"}]

let b = a.reduce((acc, val) => {
  let id = val.id
  let idx = acc.findIndex((e) => e.id == id);
  let subj = { id: id }
  let predicate = val['predicate'].split('OfUser')[0]
  subj[predicate] = val['subject']
  if (-1 == idx) {
    acc.push(subj);
  } else {
    acc[idx] = Object.assign(acc[idx], subj);
  }
  return acc
}, [])

console.log(b);

//[ { id: '3f540200-58b9-40a5-91c2-faafec75216f',
//    name: 'Hadji Singh',
//    department: 'Adventurer' },
//  { id: '41376a49-34ee-4ed8-b5f5-3f8c92b107f8',
//    name: 'Race Roger Bannon',
//    department: 'Bodyguard' },
//  { id: '9575cf33-8992-4763-81bb-fc640ffa3545',
//    name: 'Jessie Bannon',
//    department: 'Adventurer' } ]

【讨论】：