socket.accept() 在类中运行时返回无效参数

Question

这是我第一次尝试使用 python 自定义游戏/界面。我已经开始从控制器连接到游戏服务器所需的通信。我想让通信成为一个对象，以便我可以在游戏中调用它。我遇到的问题是，当我调用 server.serverRun() 时，我得到一个异常 OSError: [WinError 10022] An invalid argument was provided。现在，当在对象之外时，这一切都运行良好。我不确定我错过了什么。

'''

#game.py
import math,random,sys,time,os
import comm

serverStatus = False

while True:
    server = comm.server()
    if serverStatus == False:
        serverStatus = server.serverStart("127.0.0.1",1234)
    else:
        server.serverRun()



#comm.py
import os,socket,pickle,select

class server():

    HeaderLength = 10
    GameStatus = {"state": 0, "Sound" : 0}

    def __init__(self):
        self.clients = {}
        self.clientSocket = ""
        self.clientAddress = ("",0)
        # Create a socket
        # socket.AF_INET - address family, IPv4, some other possible are AF_INET6, AF_BLUETOOTH, AF_UNIX
        # socket.SOCK_STREAM - TCP, conection-based, socket.SOCK_DGRAM - UDP, connectionless, datagrams, socket.SOCK_RAW - raw IP packets
        self.serverSocket = socket.socket(socket.AF_INET, socket.SOCK_STREAM)

        # SO_ - socket option
        # SOL_ - socket option level
        # Sets REUSEADDR (as a socket option) to 1 on socket
        self.serverSocket.setsockopt(socket.SOL_SOCKET, socket.SO_REUSEADDR, 1)

    def serverStart(self,IP,PORT):
        try:

            # Bind, so server informs operating system that it's going to use given IP and port
            # For a server using 0.0.0.0 means to listen on all available interfaces, useful to connect locally to 127.0.0.1 and remotely to LAN interface IP
            self.serverSocket.bind((IP, PORT))

            # This makes server listen to new connections
            self.serverSocket.listen(5)
            print (f"IP Adddress: {IP}")
            print (f"Port #: {PORT}")
            return True

        except:
            print ("Connection Error")
            return False

    def serverRun(self):
        self.clientSocket, self.clientAddress = self.serverSocket.accept()
        print(f"Address {self.clientAddress}")

'''

Answer 1

while True:
    server = comm.server()
    if serverStatus == False:
        serverStatus = server.serverStart("127.0.0.1",1234)
    else:
        server.serverRun()

您使用server = comm.server() 为循环的每次迭代创建一个新套接字。 但是您只在第一次迭代中绑定+侦听服务器套接字。 这意味着在第二次迭代中，您有一个未绑定且未准备好监听的新套接字，但您对其调用了 accept。

即第一次迭代：

server = comm.server()    # creates new socket for listener
# calls bind + listen
serverStatus = server.serverStart("127.0.0.1",1234)

第二次迭代

server = comm.server()       # creates new socket for listener
# calls accept on this new socket without calling bind+listen before -> Error
server.serverRun()

您应该执行以下操作，而不是创建这个奇怪的 while 循环：

server = comm.server()                  # creates socket - only once
server.serverStart("127.0.0.1",1234)    # calls bind+listen - only once too
while True:
    server.serverRun()                  # calls accept - for every new connection