【发布时间】:2026-01-12 13:30:01
【问题描述】:
我正在尝试执行此代码
set @id = 0;
set @the_number = 0;
set @the_message = 0;
set @selected_message = 0;
SELECT id, dest_msisdn, text_message INTO @id, @the_number, @the_message FROM incoming_sms where service_id = 6015592000101762 AND job_status = 0 limit 1;
if(@the_message LIKE '%Bank%')then
select 'h';
end if;
但我总是收到错误
if(@the_message LIKE '%Bank%')then
select 'h'' at line 1
为什么我的 if 会产生错误?
【问题讨论】:
-
你遇到了什么错误?
-
我得到的错误是
#1064 - You have an error in your SQL syntax; check the manual that corresponds to your MySQL server version for the right syntax to use near 'if(@the_message LIKE '%Bank%')then select 'h'' at line 1 -
您阅读过这方面的手册吗?你的目的是什么?
标签: mysql