IOS：从characteristic.value结果转换十六进制值

Question

我能够从外围设备中检索值作为十六进制值，我需要根据我的要求进行转换。[24/12/14 11:37:00 am] sonali_phatak：我可以看到我收到了正确的响应。来自 01117100352e36302e313100000000e55a

   01 - 01-start byte
   11 - 17(Dec) - length of responce packet
   71 - response ID
   00 - Ignore this byte

    So now out of total length 17, first 4 bytes are header, last 2 bytes are CRC. We   
  need to read remaining 11 bytes and convert them to ASCII.
  35 - 5
  2e - .
  36 - 6
  30 - 0
  2e - .
  31 - 1
  31 - 1
  So Iam getting version number from watch as 5.60.11

但我需要在字符串中显示上述值 5.60.11 并在控制台中打印。如何转换它请帮助我

Answer 1

请试试这个：

NSString *strOriginalHex= @"01117100352e36302e313100000000e55a";
NSString *strNewHexForVersion = [strOriginalHex substringWithRange:NSMakeRange(8, 14)];
NSLog(@"%@",[self stringFromHexString:strNewHexForVersion]);//5.60.11


- (NSString *)stringFromHexString:(NSString *)aStrHexString
{
    // The hex codes should all be two characters.
    if (([aStrHexString length] % 2) != 0)
        return nil;

    NSMutableString *aMutStrNewString = [NSMutableString string];
    for (NSInteger i = 0; i < [aStrHexString length]; i += 2)
    {
        NSString *hex = [aStrHexString substringWithRange:NSMakeRange(i, 2)];
        NSInteger decimalValue = 0;
        sscanf([hex UTF8String], "%x", &decimalValue);
        [aMutStrNewString appendFormat:@"%c", decimalValue];
    }

    return aMutStrNewString;
}