【发布时间】：2020-01-17 23:26:43
【问题描述】：
我在执行 Oracle 存储过程时遇到了一个奇怪的问题。在将所选数据插入另一个数据时，我能够选择令人烦恼的数据 表。
下面是导致问题的查询。
BEGIN
EXECUTE IMMEDIATE
'INSERT INTO STG_MEMBER_MONTH_1
(
MEMBER_ID
,EMPLOYER_GROUP_ID
,MEMBER_BIRTH_DATE
,SPAN_FROM_DATE
,GROUP_ID_FINAL
,GROUP_SIZE
,NAME_TO_BE_USED
,MEM_DOB
,MM
,MEMBER_AGE_FINAL
,ELIG_YEAR
,ELIG_MONTH
,AGE_BAND
)
WITH CTE_Member_Month_Group_Id_Final AS (
SELECT
a.MEMBER_ID
,a.EMPLOYER_GROUP_ID
,a.MEMBER_BIRTH_DATE
,a.SPAN_FROM_DATE
b.ACCOUNT_NUM as GROUP_ID_FINAL
from STG_MEMBER_MONTH_2 a LEFT JOIN
(SELECT DISTINCT GRP_ID,ACCOUNT_NUM from ACCOUNT_MAPPING)b
ON a.EMPLOYER_GROUP_ID= b.GRP_ID)
,CTE_Member_Month_Group_Name as (
SELECT a.*,b.GROUP_SIZE,b.GROUP_NAME as NAME_TO_BE_USED
from CTE_Member_Month_Group_Id_Final a
LEFT JOIN APP_CALENDAR b
ON a.GROUP_ID_FINAL= b.GROUP_ID
)
,CTE_Max_DOB AS (
SELECT a.MEMBER_ID,b.MEMBER_BIRTH_DATE AS MEM_DOB from
(SELECT MEMBER_ID,max(SPAN_FROM_DATE) as SPAN_FROM_DATE from CTE_Member_Month_Group_Name
GROUP BY MEMBER_ID)
LEFT OUTER JOIN CTE_Member_Month_Group_Name b
ON a.MEMBER_ID = b.MEMBER_ID
AND a.SPAN_FROM_DATE = b.SPAN_FROM_DATE)
,CTE_Age_Band_Prev AS (
SELECT a.*,b.MEM_DOB,1 as "MM"
,trunc(months_between(a.SPAN_FROM_DATE,B.MEM_DOB)/12) as "MEMBER_AGE_FINAL"
,extract(year from a.SPAN_FROM_DATE) as "ELIG_YEAR"
,extract(month from a.SPAN_FROM_DATE) as "ELIG_MONTH"
from CTE_Member_Month_Group_Name a
LEFT OUTER JOIN CTE_Max_DOB b
ON a.MEMBER_ID=b.MEMBER_ID
)
,CTE_Age_Band AS (
SELECT a.*,
CASE
WHEN ltrim("MEMBER_AGE_FINAL") < 1
THEN 'Less than one year'
WHEN ltrim("MEMBER_AGE_FINAL") > 17 and ltrim("MEMBER_AGE_FINAL") <=29
THEN '18 - 29 years'
WHEN ltrim("MEMBER_AGE_FINAL") > 29 and ltrim("MEMBER_AGE_FINAL") <=39
THEN '29 - 39 years'
ELSE 'More than 40 years'
END as "AGE_BAND"
from CTE_Age_Band_Prev a
)
SELECT * from CTE_Age_Band';
END;
/
我可以毫无问题地从 CTE_Age_Band 中选择所有内容，但无法将所选数据插入表 STG_MEMBER_MONTH_1。
我收到以下错误消息
ORA-06550: LINE 57,column 1:
PLS-00103: Encountered the symbol "," when expecting one of the following:
如果我从上面的语句中删除了最后一个 CTE CTE_Age_Band 并从插入语句中删除了列 AGE_BAND，它将被执行而没有任何错误。
修改后的逻辑如下图：
BEGIN
EXECUTE IMMEDIATE
'INSERT INTO STG_MEMBER_MONTH_1
(
MEMBER_ID
,EMPLOYER_GROUP_ID
,MEMBER_BIRTH_DATE
,SPAN_FROM_DATE
,GROUP_ID_FINAL
,GROUP_SIZE
,NAME_TO_BE_USED
,MEM_DOB
,MM
,MEMBER_AGE_FINAL
,ELIG_YEAR
,ELIG_MONTH
)
WITH CTE_Member_Month_Group_Id_Final AS (
SELECT
a.MEMBER_ID
,a.EMPLOYER_GROUP_ID
,a.MEMBER_BIRTH_DATE
,a.SPAN_FROM_DATE
b.ACCOUNT_NUM as GROUP_ID_FINAL
from STG_MEMBER_MONTH_2 a LEFT JOIN
(SELECT DISTINCT GRP_ID,ACCOUNT_NUM from ACCOUNT_MAPPING)b
ON a.EMPLOYER_GROUP_ID= b.GRP_ID)
,CTE_Member_Month_Group_Name as (
SELECT a.*,b.GROUP_SIZE,b.GROUP_NAME as NAME_TO_BE_USED from CTE_Member_Month_Group_Id_Final a
LEFT JOIN APP_CALENDAR b
ON a.GROUP_ID_FINAL= b.GROUP_ID
)
,CTE_Max_DOB AS (
SELECT a.MEMBER_ID,b.MEMBER_BIRTH_DATE AS MEM_DOB from
(SELECT MEMBER_ID,max(SPAN_FROM_DATE) as SPAN_FROM_DATE from CTE_Member_Month_Group_Name
GROUP BY MEMBER_ID)
LEFT OUTER JOIN CTE_Member_Month_Group_Name b
ON a.MEMBER_ID = b.MEMBER_ID
AND a.SPAN_FROM_DATE = b.SPAN_FROM_DATE)
,CTE_Age_Band_Prev AS (
SELECT a.*,b.MEM_DOB,1 as "MM"
,trunc(months_between(a.SPAN_FROM_DATE,B.MEM_DOB)/12) as "MEMBER_AGE_FINAL"
,extract(year from a.SPAN_FROM_DATE) as "ELIG_YEAR"
,extract(month from a.SPAN_FROM_DATE) as "ELIG_MONTH"
from CTE_Member_Month_Group_Name a
LEFT OUTER JOIN CTE_Max_DOB b
ON a.MEMBER_ID=b.MEMBER_ID
)
SELECT * from CTE_Age_Band_Prev';
END;
/
看起来最后一个 CTE 'CTE_Age_Band' 中有一些愚蠢的错误，我无法弄清楚。
【问题讨论】：
-
即使通过语法着色，您也应该看到错误。
-
那是什么？我对甲骨文很陌生。只是在做。从 sql server 到 oracle 的转换。