【问题标题】:NSArray mismatch Swift Array element typeNSArray 不匹配 Swift 数组元素类型
【发布时间】:2016-06-21 05:25:50
【问题描述】:

我正在尝试从 CoreData 在 UIPickerView 中显示项目。但我总是在pickerviews titleforrow 函数中得到NSArray element failed to match the Swift Array Element type。这是我的完整代码:

import Foundation
import UIKit
import CoreData

class Create_New: UIViewController, UIPickerViewDataSource, UIPickerViewDelegate{
    var picker = UIPickerView()
    var picker2 = UIPickerView()
    var territory: [String] = []
    var company: [Company] = []
    var facility: [String] = []
    var specialty: [String] = []
    var a = 0, b = 0, c = 0, d = 0
    override func viewDidLoad() {
        super.viewDidLoad()
        picker.delegate = self
        picker.dataSource = self

        picker2.delegate = self
        picker2.dataSource = self

    }
    override func viewWillAppear(animated: Bool) {
        super.viewWillAppear(animated)

        var appDel:AppDelegate = (UIApplication.sharedApplication().delegate as! AppDelegate)
        var context:NSManagedObjectContext = appDel.managedObjectContext
        let fetchRequest = NSFetchRequest(entityName:"Company")
        let fetchRequestTerritory = NSFetchRequest(entityName:"Territory")
        let fetchRequestFacility = NSFetchRequest(entityName:"Facility")
        let fetchRequestSpecialty = NSFetchRequest(entityName:"Specialty")
        let error:NSError

        do {
            let company_temp = try context.executeFetchRequest(fetchRequest)

            company = company_temp as! [Company]
            a = company_temp.count
            print(company.count)

            let territory_temp = try context.executeFetchRequest(fetchRequestTerritory)
            territory = territory_temp.flatMap{ $0 as? String }
            b = territory_temp.count
            print(territory_temp.count)

            let facility_temp = try context.executeFetchRequest(fetchRequestFacility)
            facility = facility_temp.flatMap{ $0 as? String }
            c = facility_temp.count
            print(facility_temp.count)

            let specialty_temp = try context.executeFetchRequest(fetchRequestSpecialty)
            specialty = specialty_temp.flatMap{ $0 as? String }
            d = specialty.count
            print(specialty_temp.count)

        } catch let error as NSError {
            // failure
            print("Fetch failed: \(error.localizedDescription)")
        }


         }
    func numberOfComponentsInPickerView(pickerView: UIPickerView) -> Int {
        return 1
    }

    func pickerView(pickerView: UIPickerView, numberOfRowsInComponent component: Int) -> Int {
        var x = 1
        if (pickerView.tag == 1){
            //print(territory.count)
            return b
        }else if (pickerView.tag == 2){
            //print(company.count)
            return a
        }else if (pickerView.tag == 3){
            //print(facility.count)
            return c
        }else if (pickerView.tag == 4){
            //print(specialty.count)
            return d
        }
        return x
    }

    func pickerView(pickerView: UIPickerView, didSelectRow row: Int, inComponent component: Int) {


    }
    func pickerView(pickerView: UIPickerView, widthForComponent component: Int) -> CGFloat {
        return 200
    }

    func pickerView(pickerView: UIPickerView, titleForRow row: Int, forComponent component: Int) -> String? {
        var temp: [String] = []
                if (pickerView.tag == 1){
            return  company[a-1].name! as String
        }else if (pickerView.tag == 2){
            return company[a-1].name
        }else if (pickerView.tag == 3){
            return company[a-1].name
        }else if (pickerView.tag == 4){
            return  company[a-1].name
        }
        return temp[row]
    }
} 

我当时想做的是从 Coredata 中获取一些记录并将它们放入一个数组中,就像您在我的变量声明中看到的一样。但我收到错误AnyObject cannot be converted to String。 对不起这个简单的问题。我是 Swift 和 iOS 开发的新手。

编辑: 我从这一行得到错误:return company[a-1].name! as String

这是我的公司课程:

import Foundation
import CoreData


class Company: NSManagedObject {

// Insert code here to add functionality to your managed object subclass

}

xc模型:

我刚刚从输出窗口中注意到了这段文字: 无法为实体“公司”加载名为“公司”的类。找不到类,改用默认的 NSManagedObject。

【问题讨论】:

  • 更改公司[a-1].name! as String to company[a-1].name as!字符串
  • 我收到错误:Downcast from 'String?' to 'String' only unwraps optionals; did you mean to use '!'?
  • 好的,然后放!在行尾,比如 company[a-1].name as String!
  • 或者直接返回 company[a-1].name!
  • 请参阅this answer 关于“无法加载名为...的类”错误。

标签: ios swift core-data


【解决方案1】:

首先将数据模型文件中Company类的Module设置为Current Product Module

Company 中的属性name 似乎被声明为可选String,并且由于该方法还返回一个可选String,所以可能很简单

return company[a-1].name

【讨论】:

    【解决方案2】:

    as 强制转换只能用于保证成功的强制转换(我认为是从 Swift 1.2 开始)。如果你真的想强制强制转换,因为你知道它是有效的,你可以使用as!,但在这些情况下我总是使用as?,然后处理返回的可选值。

    你可以改变:

     return company[a-1].name! as String
    

    到:

    return company[a-1].name as? String
    

    因为该方法无论如何都会返回一个可选的。如果没有,您可以使用 nil-coalescing 处理 nil 情况:

    return company[a-1].name as? String ?? "-"
    

    其中“-”是一个合适的后备选项。

    【讨论】:

    • 我收到一个错误:Downcast from 'String?' to 'String' only unwraps optionals; did you mean to use '!'? 我可能已经在使用 Swift 2
    • 根据前面的错误,我还以为是AnyObject。 (您将使用 Swift 2。我只是注意到它来自旧教程。)
    • 我认为 vadian 的回答更符合目标。我认为关于无法加载类的注释是关键信息。
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