在 OpenCV Python 中裁剪矩形

Question

我有一个像 this

我想从书架上剪下每一本书。我是用这段代码开始的。

thresh = cv2.adaptiveThreshold(blur, 255, 1, 1, 11, 2)

cv2.imshow("Gray", gray)
cv2.waitKey(0)

cv2.imshow("Blurred", blur)
cv2.waitKey(0)

# detect edges in the image
edged = cv2.Canny(img, 10, 250)
cv2.imshow("Edged", edged)
cv2.waitKey(0)

# construct and apply a closing kernel to 'close' gaps between 'white'
# pixels
kernel = cv2.getStructuringElement(cv2.MORPH_RECT, (1, 6))
closed = cv2.morphologyEx(edged, cv2.MORPH_CLOSE, kernel)
cv2.imshow("Closed", closed)
cv2.waitKey(0)

# loop over the contours
for contour in contours:

    # peri = cv2.arcLength(contour, True)
    # approx = cv2.approxPolyDP(contour, 0.02 * peri, True)
    # r = cv2.boundingRect(contour)
    if len(contour) >= 4:
        index += 1
        x, y, w, h = cv2.boundingRect(contour)
        roi = img[y:y+h, x:x+w]
        # cv2.imwrite("a/" + "book - " + str(index) + '.jpg', roi)
        draw_contour = cv2.drawContours(img, [contour], -1, (255, 140, 240), 2)
        total += 1

print contour

cv2.imshow("Drawed Contour", img)
cv2.waitKey(0)

我在书架上的每本书中都创建了一个边界框，但不幸的是，这给了我output。我只想在书籍的侧面/角落绘制一个边界框，然后从边界框中裁剪它。

Answer 1

我认为您不能仅使用此代码明确识别书籍，但您可以在代码中做的一项快速改进是绘制面积大于某个值的轮廓。以下代码sn-p

 if len(contour) >= 4:
    index += 1
    x, y, w, h = cv2.boundingRect(contour)
    roi = img[y:y+h, x:x+w]
    # cv2.imwrite("a/" + "book - " + str(index) + '.jpg', roi)
    if cv2.contourArea(contour) > 200:
        draw_contour = cv2.drawContours(img, [contour], -1, (255, 140, 240), 2)
        total += 1