连接两个具有相同类型连接的查询答案

【问题标题】：Joining two queries having same kind of joins连接两个具有相同类型连接的查询
【发布时间】：2017-03-09 15:29:02
【问题描述】：

我有两个问题。两者仅在一个连接条件上有所不同。有没有办法让它成为一个单一的查询。下面是查询。

第一个查询：

delete from Employee where Employee_ID in    
  (    
    select PK from Dept    
     inner join Tran on Tran.PK = Dept.TX_ID   
        inner join TASK on TASK.TRANSINFO = TRAN.PK_ID   
        inner join TASK1 on TASK.PT_ID = TASK1.PK_ID  
           inner join TASKSUB on TASKSUB.PK_ID = TASK1.SUBJECT   
  where TASKSUB. PK1 in (select id  from tmp) and TASKSUB.REF= ‘Shopping’
  );

第二次查询：

    delete from Employee where Employee_ID in   
      (   
  select PK from Dept   
    inner join Tran on Tran.PK = Dept.TX_ID   
     inner join TASK on TASK.TRANSINFO = TRAN.PK_ID   
      inner join TASK1 on TASK.PT_ID = TASK1.PK_ID   
         inner join TASKSUB on TASKSUB.PK_ID = TASK1.SUBJECT   
  where TASKSUB. PK1 in (select id1  from tmp) and TASKSUB.REF= ‘Shopping’   
  );

唯一的区别是tmp表中的id和id1。

提前致谢

【问题讨论】：

标签： sql oracle

【解决方案1】：

也许在 id 和 id1 的子选择中使用UNION。像

select id from table1 
union 
select id1 from table1

【讨论】：

【解决方案2】：

delete from Employee where Employee_ID in    
(    
select PK from Dept    
 inner join Tran on Tran.PK = Dept.TX_ID   
    inner join TASK on TASK.TRANSINFO = TRAN.PK_ID   
    inner join TASK1 on TASK.PT_ID = TASK1.PK_ID  
       inner join TASKSUB on TASKSUB.PK_ID = TASK1.SUBJECT   
where TASKSUB. PK1 in (select id from tmp union all select id1 from tmp) and TASKSUB.REF= ‘Shopping’
)

【讨论】：

【解决方案3】：

试试这个：

delete from Employee where Employee_ID in    
(    
    select PK from Dept    
    inner join Tran on Tran.PK = Dept.TX_ID   
    inner join TASK on TASK.TRANSINFO = TRAN.PK_ID   
    inner join TASK1 on TASK.PT_ID = TASK1.PK_ID  
    inner join TASKSUB on TASKSUB.PK_ID = TASK1.SUBJECT   
    where TASKSUB. PK1 in (select id  from tmp) and TASKSUB.REF= ‘Shopping’

    union

    select PK from Dept   
    inner join Tran on Tran.PK = Dept.TX_ID   
    inner join TASK on TASK.TRANSINFO = TRAN.PK_ID   
    inner join TASK1 on TASK.PT_ID = TASK1.PK_ID   
        inner join TASKSUB on TASKSUB.PK_ID = TASK1.SUBJECT   
    where TASKSUB. PK1 in (select id1  from tmp) and TASKSUB.REF= ‘Shopping’
  );

【讨论】：

【解决方案4】：

这个怎么样？

where EXISTS (
        select 1 from tmp 
        where TASKSUB.PK1 = tmp.id or TASKSUB.PK1 = tmp.id1
    ) and 
    TASKSUB.REF= ‘Shopping’

【讨论】：