Tkinter 绑定到函数内部

Question

目前这是我的代码：

from tkinter import *

class Application(Frame):

    def a(self, event = None):

        print ("a")

    def create_widgets(self):

        def b(event = None):

            print(entry.get())

        entry = Entry()
        entry.grid(row = 1, column = 1)
        Button(text = "b", command = b).grid(row = 1, column = 2)

    def __init__(self, master = None):
        Frame.__init__(self, master)
        self.grid()
        self.create_widgets()
        master.bind("<Return>", b)

root = Tk()
app = Application(master = root)
app.mainloop()

到目前为止，它调用了 a，但是将 self.a 替换为 self.b 以使其调用 b 会引发 AttributeError: 'Application' object has no attribute 'b' and with just b returns a NameError: 'b' is未定义。

那么我怎样才能像按钮一样进行绑定调用？

Answer 1

那么我怎样才能像按钮一样进行绑定调用b呢？

在我看来，最好的解决方案是使b 成为类的正确方法，而不是嵌套函数。使您的小部件也具有适当的属性，并且代码变得更容易编写：

class Application(Frame):
    def a(self, event = None):
        print ("a")

    def b(self, event = None):
        print(self.entry.get())

    def create_widgets(self):
        self.entry = Entry()
        self.entry.grid(row = 1, column = 1)
        Button(text = "b", command = b).grid(row = 1, column = 2)

    def __init__(self, master = None):
        ...
        master.bind("<Return>", self.b)