日期上的雄辩联接表

Question

点击表架构：

user_id as (integer)
created_at as (Y-m-d H:i:s)

查看表

user_id as (integer)
created_at as (Y-m-d H:i:s)

我需要按日期而不是日期时间计算第一个表 + 第二个表组中的记录：

现在我正在使用 2 个查询：

$clicks = $user->clicks()
->select(\DB::raw("DATE_FORMAT(created_at, '%d/%m/%Y') as date"),
        \DB::raw("COUNT(*) as clicks"))
->groupBy('date')
->orderBy('date', 'ASC')
->get()->toArray();

$views = $user->views()
->select(\DB::raw("DATE_FORMAT(created_at, '%d/%m/%Y') as date"),
    \DB::raw("COUNT(*) as views"))
->groupBy('date')
->orderBy('date', 'ASC')
->get()->toArray();

在我有一个循环之后

$out = [];
    for ($i=0; $i < count($views); $i++) { 
        $out[] = [
            'date' => $views[$i]['date'],
            'clicks' => $clicks[$i]['clicks'],
            'views' => $views[$i]['views']
        ];
    }

但是这样如果点击存在并且在某个日期查看 no 它不会将它添加到数组中 可以按日期格式加入 created_at 吗？没时间？

Answer 1

因为 MySQL 不支持全连接试试这个

select date(clicks.created_at)as 'Date',
count(clicks.user_id) as 'clicks',
count(views.user_id)as 'views'
from clicks
left join views on date(views.created_at)=date(clicks.created_at)
group by date(clicks.created_at)

union

select date(views.created_at)as 'Date',
count(clicks.user_id) as 'clicks',
count(views.user_id)as 'views'
from views
left join clicks  on date(views.created_at)=date(clicks.created_at)
group by date(views.created_at)

由于您的查询中有计数，请尝试此查询

select a.Date,a.clicks,b.views
 from(select date(clicks.created_at)as 'Date',
       count(clicks.user_id) as 'clicks'
       from clicks
       group by date(clicks.created_at))a
 left join (select date(views.created_at)as 'Date',
       count(views.user_id) as 'views'
       from views
       group by date(views.created_at))b
 on a.date=b.date    

union

select a.Date,b.clicks,a.views
 from(select date(views.created_at)as 'Date',
       count(views.user_id) as 'views'
       from views
       group by date(views.created_at))a
 left join (select date(clicks.created_at)as 'Date',
       count(clicks.user_id) as 'clicks'
       from clicks
       group by date(clicks.created_at))b
 on a.date=b.date