Laravel 错误 - 试图获取非对象的属性游戏

Question

我正在尝试运行一个查询来计算用户参与活动的次数，但我收到了以下错误：

试图获取非对象的属性“游戏”

还有下划线：

<td><?php echo e($player->game); ?></td>

我已经写好了查询

控制器

$players = DB::table("played_game")
    ->select("played_game.user_id","played_game.game","users.username", DB::raw("COUNT(played_game.game) as no_game"))
    ->join("users","users.id","=","played_game.user_id")
    ->groupBy("played_game.game","users.username","played_game.user_id")
    ->orderByRaw('COUNT(played_game.game) DESC')
    ->paginate(15);

查看

@foreach ($players as $key => $player_list)
    <tr>
        <th colspan="3"
            style="background-color: #F7F7F7">{{ $player_list->username }}</th>
    </tr>
    @foreach ($player_list as $player)
        <tr>
            <td>{{ $player->game }}</td>
            <td>{{ $player->no_game }}</td>
        </tr>
    @endforeach
@endforeach 

我想在 td 中显示涉及 colspan 的玩家（用户名）和其他详细信息。

Answer 1

paginate() 返回一个Illuminate\Pagination\LengthAwarePaginator 的实例，它扩展了具有items() 等功能的AbstractPaginator，查看它以了解更多有用的功能。

要获得分页结果，请执行->paginate(15)->items()，也可以执行all()、toArray()、toJson() 等，因为它实现了许多接口。