从xml插入多条记录

Question

我想批量插入到 PostgreSQL 数据库中：后端代码会创建类似于

的 XML

<items>
   <i dt="2014-08-01" name="vvv" count="12" />
   <i dt="2014-08-02" name="zzz" count="6" />
</items>

我想将其传递给函数并一次性保存所有值。

但我被困在xpath：每个“列”似乎都是一个值数组，我不知道如何将它们插入到表中。这是一个测试示例：

CREATE TEMP TABLE temp_values (dt date, name varchar, count int);

WITH x AS (SELECT '
  <items>
    <i dt="2014-08-01" name="vvv" count="12" />
    <i dt="2014-08-02" name="zzz" count="6" />
    <i dt="2014-08-03" name="bbd" count="10" />
  </items>'::xml AS t
)
INSERT INTO temp_values
SELECT 
  xpath('/items/i/@dt', t),
  xpath('/items/i/@name', t),
  xpath('/items/i/@count', t)
FROM  x;

现在，最后我希望temp_values 有 3 条记录，就像在 XML 中一样，但表是空的。

如果您注释掉“插入”行，您会看到这些值被正确解析。只是它返回单个记录，其中每列是一个数组，而不是返回多个记录。

我错过了什么？

Answer 1

好的，显然unnest 和数组索引是解决方案：

unnest(数组) |将数组扩展为一组行

所以代码是

CREATE TEMP TABLE temp_values (dt date, name varchar, count int) ON COMMIT DROP;

WITH x AS (SELECT '
  <items>
    <i dt="2014-08-01" name="vvv" count="12" />
    <i dt="2014-08-02" name="zzz" count="6" />
    <i dt="2014-08-03" name="bbd" count="10" />
  </items>'::xml AS t
)
INSERT INTO temp_values
SELECT 
  CAST(CAST((xpath('//@dt', node))[1] as varchar) as date),
  CAST((xpath('//@name', node))[1] as varchar),
  CAST(CAST((xpath('//@count', node))[1] as varchar) as int)
FROM (SELECT unnest(xpath('/items/i', t)) AS node FROM x) sub;

SELECT * FROM temp_values

Answer 2

我希望在@: 之前删除一些多余的斜线

CREATE TEMP TABLE temp_values (dt date, name varchar, count int) ON COMMIT DROP;

WITH x AS (SELECT '
  <items>
    <i dt="2014-08-01" name="vvv" count="12" />
    <i dt="2014-08-02" name="zzz" count="6" />
    <i dt="2014-08-03" name="bbd" count="10" />
  </items>'::xml AS t
)
INSERT INTO temp_values
SELECT 
  CAST(CAST((xpath('@dt', node))[1] as varchar) as date),
  CAST((xpath('@name', node))[1] as varchar),
  CAST(CAST((xpath('@count', node))[1] as varchar) as int)
FROM (SELECT unnest(xpath('/items/i', t)) AS node FROM x) sub;

SELECT * FROM temp_values