【发布时间】:2021-01-16 15:13:26
【问题描述】:
我目前正在整理一些代码,允许用户以多种方式搜索活动表(即,如果选中标题复选框)我觉得我的代码看起来有点乱,所以我想来堆栈溢出和问大家什么是让这段代码更优雅的最好方法?我只是在寻找改进的方法,拥有更易读的代码,以及更好的结构。
if (request('name')){
$name = request('name');
$user = User::where('name', $name)->firstOrFail();
if (request('title') == 1) {
$activities = Activity::with('activity')->where('user_id', $user->id)->whereHas('thread', function ($query) use ($search, $user) {
$query->where('threads.user_id', '=', $user->id)
->where('threads.title', 'LIKE', '%' . $search . '%');
})->get();
dd($activities);
} else {
$activities = Activity::with('activity')->where('user_id', $user->id)->whereHas('thread', function ($query) use ($search, $user) {
$query->where('threads.user_id', '=', $user->id)
->where('threads.title', 'LIKE', '%' . $search . '%')
->orWhere('threads.body', 'LIKE', '%' . $search . '%');
})->orWhereHas('reply', function ($query) use ($search, $user) {
$query->where('replies.user_id', '=', $user->id)
->where('replies.body', 'LIKE', '%' . $search . '%');
})->get();
dd($activities);
}
} else {
if (request('title') == 1) {
$activities = Activity::with('activity')->where('user_id', $user->id)->whereHas('thread', function ($query) use ($search, $user) {
$query->where('threads.title', 'LIKE', '%' . $search . '%');
})->get();
dd($activities);
} else {
$activities = Activity::with('activity')->whereHas('thread', function ($query) use ($search) {
$query->where('threads.body', 'LIKE', '%' . $search . '%')
->orWhere('threads.title', 'LIKE', '%' . $search . '%');
})->orWhereHas('reply', function ($query) use ($search) {
$query->where('replies.body', 'LIKE', '%' . $search . '%');
})->get();
}
}
谢谢!
【问题讨论】:
-
您可以使用查询构建器的
when和unless方法以及在模型中定义一些查询范围
标签: laravel