Yii2 查询 foreach 循环内的搜索模型答案

【问题标题】：Yii2 query of search model inside foreach loopYii2 查询 foreach 循环内的搜索模型
【发布时间】：2017-11-03 07:43:11
【问题描述】：

这是我的代码，但它只输出最后插入的用户。我的意思是它不显示注册到特定企业的其他用户。用户应该只看到在他的公司注册的用户。在此先感谢

我正在使用yii2 高级。

我有 3 张桌子

第一个表 - user_tbl（user.id、user.username、user.email）
第二张表 - userinfo_tbl(info.id, info.userid, info.business id)

第三张表 - Business_tbl(business.id, business.name)

 public function search($params)
    {
     //current user logedin
         $CurrentUserID = Yii::$app->user->getId();

    //Find business to which current user is registered
         $BusinessID = Yii::$app->mycomponent->getBusinessID($CurrentUserID);

    //Now find all the users with this business id
        $BusinessUsers=  Yii::$app->mycomponent->getBusinessUsersID($BusinessID);

         foreach ($BusinessUsers as $BusinessUser)
             {
             $UID=$BusinessUser['user_id'];

             }

        $query = User:: find()->where(['id'=>$UID]); 

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
            'sort'=> ['defaultOrder' => ['id'=>SORT_ASC]],
            'pagination' => [
                'pageSize' => $this->_pageSize,
            ]
        ]);

【问题讨论】：

请告诉我们getBusinessUsersID方法代码。在 foreach 中，您每次都分配 $UID= 并覆盖最后一个值。就目前而言，这段代码毫无意义。
$UID[] = $BusinessUser['user_id'];

标签： php yii2

【解决方案1】：

在您的代码中 = $UID 应该是一个数组，否则它将始终只有一个 id。 $businessUsers 中的最后一个。将您的代码更改为：

    public function search($params)
{
 //current user logedin
     $CurrentUserID = Yii::$app->user->getId();

//Find business to which current user is registered
     $BusinessID = Yii::$app->mycomponent->getBusinessID($CurrentUserID);

//Now find all the users with this business id
    $BusinessUsers=  Yii::$app->mycomponent->getBusinessUsersID($BusinessID);

    //check if $BusinessUsers has records...
    $UID = yii\helpers\ArrayHelper::getColumn($BusinessUsers, 'user_id');
    $query = User:: find()->where(['in','id', $UID]); 
    $dataProvider = new ActiveDataProvider([
        'query' => $query,
        'sort'=> ['defaultOrder' => ['id'=>SORT_ASC]],
        'pagination' => [
            'pageSize' => $this->_pageSize,
        ]
    ]);
}

【讨论】：

【解决方案2】：

试试这个简单的方法

public function search($params)
{
    //current user logedin
    $CurrentUserID = Yii::$app->user->getId();

    //Find business to which current user is registered
    $BusinessID = Yii::$app->mycomponent->getBusinessID($CurrentUserID);

    //Now find all the users with this business id
    $BusinessUsers=  Yii::$app->mycomponent->getBusinessUsersID($BusinessID);
    $UID = yii\helpers\ArrayHelper::map($BusinessUsers,'user_id','user_id');

    $query = User:: find()->where(['id'=>$UID]); 
    $dataProvider = new ActiveDataProvider([
        'query' => $query,
        'sort'=> ['defaultOrder' => ['id'=>SORT_ASC]],
        'pagination' => [
            'pageSize' => $this->_pageSize,
        ]
    ]);

【讨论】：

【解决方案3】：

您可能希望将所有 ID 放在逗号分隔的列表中，然后在 where 条件中使用 IN 查询。

public function search($params)
    {
     //current user logedin
         $CurrentUserID = Yii::$app->user->getId();

    //Find business to which current user is registered
         $BusinessID = Yii::$app->mycomponent->getBusinessID($CurrentUserID);

    //Now find all the users with this business id
        $BusinessUsers=  Yii::$app->mycomponent->getBusinessUsersID($BusinessID);

         foreach ($BusinessUsers as $BusinessUser)
             {
             array_push($UID,$BusinessUser['user_id']); //put all IDs in an array
             }
        $UID = implode(',',$UID); //making it look like this 1,2,3,4
        $query = User:: find()->where('id IN ('.$UID.')'); 

        $dataProvider = new ActiveDataProvider([
            'query' => $query,
            'sort'=> ['defaultOrder' => ['id'=>SORT_ASC]],
            'pagination' => [
                'pageSize' => $this->_pageSize,
            ]
        ]);

【讨论】：