【发布时间】:2013-11-26 08:53:54
【问题描述】:
我有一个带有一些输入字段的引导弹出表单。我在表单中添加了一个提交按钮,它会触发客户端 JS 验证。但是,当单击按钮时,输入字段的当前值并没有被 jQuery 的 val() 方法捕获:我只是得到一个空字符串。
这里是标记:
<div class="popover fade right in" style="top: -154.5px; left: 249px; display: block;">
<div class="arrow">
</div>
<h3 class="popover-title">New Job Site contact</h3>
<div class="popover-content">
<form class="popover-form form-horizontal" id="newjobsite_contact_form" accept-charset="utf-8" method="post" action="http://dev.temperature/home/#">
<div class="form-group">
<div class=" required ">
<input type="text" class="form-control" id="popover-first_name" required="1" placeholder="First name" value="" name="first_name">
</div>
<div class=" required ">
<input type="text" class="form-control" required="1" placeholder="Surname" value="" name="surname">
</div>
<div class=" required ">
<input type="text" class="form-control" required="1" placeholder="Phone" value="" name="phone">
</div>
<div class="">
<input type="text" class="form-control" placeholder="Mobile" value="" name="mobile">
</div>
<div class="">
<input type="email" class="form-control" placeholder="Email" value="" name="email">
</div>
<div class="">
<input type="url" class="form-control" placeholder="Website" value="" name="website">
</div>
</div>
<div class="popover_buttons">
<button class="btn btn-success" onclick="submit_newjobsite_contact(); return false;" type="button" id="newjobsite_contact_submit">Submit</button>
<button class="btn btn-warning" onclick="close_newjobsite_contact(); return false;" type="button" id="newjobsite_contact_cancel">Cancel</button>
</div>
</form>
</div>
</div>
这里是 JS:
function submit_newjobsite_contact() {
errors_found = validate_popover_form($('#newjobsite_contact_form'));
if (errors_found.length == 0) {
// Form values submitted to PHP code through AJAX request here
} else {
error_msg = "Please check the following errors:\n";
$(errors_found).each(function(key, item) {
error_msg += "- "+item.message+"\n";
});
alert(error_msg);
}
}
function validate_popover_form(form_element) {
found_errors = [];
$('span.error').remove();
form_element.find('select,input').each(function(key, item) {
if ($(item).attr('required') && $(item).val().length == 0) {
found_error = true;
found_errors.push({elementname: $(item).attr('name'), message: "A value for "+$(item).attr('placeholder')+" is required"});
}
console.log($(item).val()); // More validation here, just putting debugging code instead
});
return found_errors;
}
我做错了什么?这些输入字段的所有其他属性都被 jQuery 正确检索,而不是我在其中输入文本后的值。
【问题讨论】:
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奇怪的是,当我把它放到fiddle 中时它工作正常,但它在我自己的页面上不起作用。我猜bootstrap的popover JS在某种程度上弄乱了jquery。
标签: javascript jquery html twitter-bootstrap