Laravel - 根据用户查询

Question

在 Laravel 中，我有一个场景，不同的用户可以转到视图刀片，在那里他们可以看到他们创建的帖子。

目前我只是传递所有数据，但我想知道如何根据用户将数据传递给视图。

例如，如果我是 root 用户，我可以看到所有类似的东西

Post::get()

然后

return view('someview', compact('post')

哪个会返回帖子

基本上我正在尝试的是这样的......

if(user->role = their role) then you get query 1 else you get query 2

您认为使用条件查询范围可以实现这一点吗？

更新

这是一个可怕的解决方案吗？

if($user->department == "Loans")
{
    echo "you are from loans FAM";
    $articles = Article::where('department', '=', 'Loans')->get();
} 
else if($user->department == "Digital")
{
    echo "you are from digital FAM";
    $articles = Article::where('department', '=', 'Digital')->get();
} 
else if($user->department == "Consulting")
{
    echo "you are from Consulting FAM";
    $articles = Article::where('department', '=', 'Consulting')->get();
} 

Answer 1

如果您愿意，可以使用查询范围来实现。像这样的：

class Post extends Model
{
    // ...

    public function scopeByUser($query, User $user)
    {
        // If the user is not an admin, show only posts they've created
        if (!$user->hasRole('admin')) {
            return $query->where('created_by', $user->id);
        }

        return $query;
    }
}

那么你可以这样使用它：

$posts = Post::byUser($user)->get();

---

响应您的更新：

class Article extends Model
{
    // ...

    public function scopeByUser($query, User $user)
    {
        // If the user is not an admin, show articles by their department.
        // Chaining another where(column, condition) results in an AND in
        // the WHERE clause
        if (!$user->hasRole('admin')) {
            // WHERE department = X AND another_column = another_value
            return $query->where('department', $user->department)
                ->where('another_column', 'another_value');
        }

        // If the user is an admin, don't add any extra where clauses, so everything is returned.
        return $query;
    }
}

您可以按照与上述相同的方式使用它。

Article::byUser($user)->get();