【发布时间】:2017-06-20 19:03:20
【问题描述】:
我从遵循此模式的 API 接收动态 JSON:
{
"ts": timestamp,
"data": [
[ code1, payload1 ],
[ code2, payload2 ],
...
]
}
例如原始数据将是:
var streamSnapshot = []byte(
`{
"ts": 1496244373.04,
"data":[
["xrate", {"rate":1.2916,"ccy":"USD"}],
["balance",
{
"open_stake":["GBP", 0.0],
"balance":["GBP", 0.0]
}
],
["event",
{
"competition_id":"545",
"ir_status":"pre_event",
"start_time":"2017-09-10T17:00:00+00:00",
"competition_name":"USA NFL",
"event_id":"2017-09-10,21617,21635",
"home":"Buffalo Bills",
"away":"New York Jets",
"sport":"af",
"competition_country":"US"
}
],
["sync", {"Token":"eb1c57132d004f8d8fb967c076921fac"}]
]
}`)
考虑到我们希望避免解组为这样的结构:
type StreamMessage struct {
Data [][]interface{} `json:"data"`
Ts float64 `json:"ts"`
}
我们必须像这样将数据转换回:
m := raw.(map[string]interface{})
switch messageType {
case XRATE:
xrate := XRate{
Message: Message{
Type: XRATE,
TimeStamp: msg.Ts,
},
rate: m["rate"].(float64),
ccy: m["ccy"].(string),
}
...
解组的更好方法是什么?
【问题讨论】:
标签: json go unmarshalling