TypeError: __init__() 接受 1 个位置参数，但给定了 2 个 discord.py

Question

所以我试图在我的机器人中创建一个设置命令，用户可以在其中选择他想要的内容。问题是我无法让它按我的意愿工作。

我有这个作为我的代码

# Function to write changes to file
def set_adminrole(guild: Guild, *, role: Role):
    with open("admins.json") as f:
        roles = json.load(f)

    roles[str(guild.id)] = role.id

    with open("admins.json", 'w') as f:
        json.dump(roles, f, indent=4)

# Actual command

-- Not important code --

await ctx.send(f"Now, mention the role you want it to be the admin role")
    role: Message = await bot.wait_for("message", check=check)
    actualrole: Role = Role(role)
    set_adminrole(ctx.message.guild, role=actualrole)
    await ctx.send(f"Admin role changed to {Role(role.content).mention}... Let's keep going")

当我提到将其设置为管理员角色的角色时，它会引发此错误：

Ignoring exception in command setup:
Traceback (most recent call last):
  File "C:\Users\xlysa\AppData\Local\Programs\Python\Python38-32\lib\site-packages\discord\ext\commands\core.py", line 85, in wrapped
    ret = await coro(*args, **kwargs)
  File "D:/Ficheiros/Pastas/Tudo/Coding/Python/Projects/Server-Utils/bot.py", line 262, in start_setup
    actualrole: Role = Role(role)
TypeError: __init__() takes 1 positional argument but 2 were given

The above exception was the direct cause of the following exception:

Traceback (most recent call last):
  File "C:\Users\xlysa\AppData\Local\Programs\Python\Python38-32\lib\site-packages\discord\ext\commands\bot.py", line 903, in invoke
    await ctx.command.invoke(ctx)
  File "C:\Users\xlysa\AppData\Local\Programs\Python\Python38-32\lib\site-packages\discord\ext\commands\core.py", line 855, in invoke
    await injected(*ctx.args, **ctx.kwargs)
  File "C:\Users\xlysa\AppData\Local\Programs\Python\Python38-32\lib\site-packages\discord\ext\commands\core.py", line 94, in wrapped
    raise CommandInvokeError(exc) from exc
discord.ext.commands.errors.CommandInvokeError: Command raised an exception: TypeError: __init__() takes 1 positional argument but 2 were given

感谢您的帮助

Answer 1

因此您收到一条消息，然后尝试使用该消息创建角色对象。这没有任何意义。查看 Role 对象的构造函数，并正确调用它。

await ctx.send(f"Now, mention the role you want it to be the admin role")
    role: Message = await bot.wait_for("message", check=check)
    actualrole: Role = Role(role) #<- what are you doing here????
    set_adminrole(ctx.message.guild, role=actualrole)
    await ctx.send(f"Admin role changed to 

Answer 2

我检索到消息的内容，即<@&123456789> 是123456789 我提到的角色的ID。从字符串中删除了<, @, & and >，只剩下了id。刚刚使用discord.utils.get(ctx.guild.roles, id=123456789) 和繁荣。谢谢大家的帮助